Question

我想构建一个使用C＃XML RSAKeys构建的公钥，但是我想用java重建它，问题是我收到了M＆amp; E本身来自Key作为字节值，并构造密钥我将使用两个BigIntegers，如何构造公钥？

编辑：问题是被解码为base64的mod，exp字节数组，是公钥的M，N ......

    byte[] mod  = Base64.decodeBase64(modulus.getBytes());
    byte[] exp  = Base64.decodeBase64(exponent.getBytes());

    int[] copyMod = new int[mod.length];

    for (int x = 0; x < mod.length; x++) {
        copyMod[x] = unsignedToBytes((byte) mod[x]);
    }

    int[] copyExp = new int[exp.length];

    for (int x = 0; x < exp.length; x++) {
        copyExp[x] = unsignedToBytes((byte) exp[x]);
    }

    String Mod =  Arrays.toString(copyMod);
    String Exp = Arrays.toString(copyExp);

    BigInteger m = new BigInteger(Mod.getBytes());
    BigInteger e = new BigInteger(Exp.getBytes());

        java.security.spec.RSAPublicKeySpec spec = new java.security.spec.RSAPublicKeySpec(m, e);
        KeyFactory keyFactory = KeyFactory.getInstance("RSA");
        PublicKey publicKey = keyFactory.generatePublic(spec);

Answer 1

您没有告诉我们您想要的对象类型。但是如果你想要一个RSA公钥，你可以做（BouncyCastle）：

RSAPublicKey rsaPubKey = new JCERSAPublicKey(
    new RSAKeyParameters(false, modulus, exponent));

请参阅class definition。

Answer 2

java.security.spec.RSAPublicKeySpec spec = new java.security.spec.RSAPublicKeySpec(m, e);
KeyFactory keyFactory = KeyFactory.getInstance("RSA");
PublicKey publicKey = keyFactory.generatePublic(spec);

从大整数构建公钥？

2 个答案: