如何在GridLayout中获取元素的X和Y索引?

时间:2011-10-09 09:55:34

标签: java swing awt grid-layout

我正在研究一个java教程,并发现在GridLayout中查找JButton的x / y索引的方法是遍历与布局关联的按钮b的二维数组,并检查是否

b[i][j] == buttonReference

  @Override
  public void actionPerformed(ActionEvent ae) {
    JButton bx = (JButton) ae.getSource();
    for (int i = 0; i < 5; i++)
      for (int j = 0; j < 5; j++)
        if (b[i][j] == bx)
        {
          bx.setBackground(Color.RED);
        }
  }

是否有更简单的方法来获取按钮的X / Y索引?

类似的东西:

JButton button = (JButton) ev.getSource();
int x = this.getContentPane().getComponentXIndex(button);
int y = this.getContentPane().getComponentYIndex(button);

this是GameWindow实例,ev当用户按下按钮时触发ActionEvent。

在这种情况下,它应该得到:x == 2,y == 1

@ GameWindow.java:

package javaswingapplication;

import java.awt.Color;
import java.awt.GridLayout;
import java.awt.event.*;
import javax.swing.*;

public class GameWindow extends JFrame implements ActionListener
{
  JButton b[][] = new JButton[5][5];

  int v1[] = { 2, 5, 3, 7, 10 };
  int v2[] = { 3, 5, 6, 9, 12 };

  public GameWindow(String title)
  {
    super(title);

    setLayout(new GridLayout(5, 5));
    setDefaultCloseOperation(EXIT_ON_CLOSE );

    for (int i = 0; i < 5; i++)
      for (int j = 0; j < 5; j++)
      {
        b[i][j] = new JButton();
        b[i][j].addActionListener(this);
        add(b[i][j]);
      }
  }

  @Override
  public void actionPerformed(ActionEvent ae) {
    ((JButton)ae.getSource()).setBackground(Color.red);
  }
}

@ JavaSwingApplication.java:

package javaswingapplication;

public class JavaSwingApplication {
  public static void main(String[] args) {
    GameWindow g = new GameWindow("Game");
    g.setVisible(true);
    g.setSize(500, 500);
  }
}

7 个答案:

答案 0 :(得分:17)

此示例显示如何创建一个知道其在网格上的位置的网格按钮。方法getGridButton()显示了如何根据网格坐标有效地获取按钮引用,并且动作侦听器显示单击和找到的按钮是相同的。

GridButtonPanel

package gui;

import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.List;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;

/**
 * @see http://stackoverflow.com/questions/7702697
 */
public class GridButtonPanel {

    private static final int N = 5;
    private final List<JButton> list = new ArrayList<JButton>();

    private JButton getGridButton(int r, int c) {
        int index = r * N + c;
        return list.get(index);
    }

    private JButton createGridButton(final int row, final int col) {
        final JButton b = new JButton("r" + row + ",c" + col);
        b.addActionListener(new ActionListener() {

            @Override
            public void actionPerformed(ActionEvent e) {
                JButton gb = GridButtonPanel.this.getGridButton(row, col);
                System.out.println("r" + row + ",c" + col
                    + " " + (b == gb)
                    + " " + (b.equals(gb)));
            }
        });
        return b;
    }

    private JPanel createGridPanel() {
        JPanel p = new JPanel(new GridLayout(N, N));
        for (int i = 0; i < N * N; i++) {
            int row = i / N;
            int col = i % N;
            JButton gb = createGridButton(row, col);
            list.add(gb);
            p.add(gb);
        }
        return p;
    }

    private void display() {
        JFrame f = new JFrame("GridButton");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.add(createGridPanel());
        f.pack();
        f.setLocationRelativeTo(null);
        f.setVisible(true);
    }

    public static void main(String[] args) {
        EventQueue.invokeLater(new Runnable() {

            @Override
            public void run() {
                new GridButtonPanel().display();
            }
        });
    }
}

答案 1 :(得分:9)

你已经保存了所有JButton的数组;您可以搜索ae.getSource()并获得该职位。

for (int i = 0; i < 5; i++) {
  for (int j = 0; j < 5; j++) {
    if( b[i][j] == ae.getSource() ) { 
      // position i,j
    }
  }
}

答案 2 :(得分:5)

来自JButtons

  • 的JButton#的setName(字符串);

  • 的JButton#setActionCommand(字符串);

  • 的JButton#的setAction(动作);

from / to Container

SwingUtilities#convert...

SwingUtilities#getDeepestComponentAt

答案 3 :(得分:1)

你可以使用setName()在JButton中创建它的位置(例如button.setName(i +“”+ j););然后,您可以通过在空格周围分割从button.getName()获得的字符串来访问它。它不是一种特别有效的方法,但它听起来有点像你现在(或者现在)正在寻找。

答案 4 :(得分:1)

这个解决方案选择像他们之间的所有对象 第一 写方法获取文本或Jbuuton或jlable所需的一切或.... 代码

下的第二次更改
public class Event_mouse implements MouseListener {

    @Override
    public void mouseReleased(MouseEvent e) {
        try {
            Everything source = (Everything) e.getSource();
             if(Everything.gettext==gol){

             }

        } catch (Exception ee) {
            JOptionPane.showMessageDialog(null, ee.getMessage());

    }

}

答案 5 :(得分:0)

我认为有更好的方法,例如,我创建了一个新的JButton类,该类从javax.swing扩展了JButton,将其命名为JButton2,然后向其添加了2个新属性(xGridPos和yGridPos),如下所示:

private class JButton2 extends JButton{
    public int xGridPos;
    public int yGridPos;
}

当我创建一个新的JButton2时,我在网格上的x和y位置设置了这个新属性,因此您可以获取x和y并将其与getSource和cast一起使用:

private class ListenerTest implements ActionListener{
    public void actionPerformed(ActionEvent theActionEvent){
        JButton2 theButton = (JButton2)actionE.getSource();
        // Use the xGridPos and yGridPos in section with theButton.xGridPos or
        // theButton.xGridPos
    }
}

我希望这对您有帮助:D。

答案 6 :(得分:0)

您不需要按钮显式存储它们的 x,y 位置。 考虑以下代码:

JComponent e=//something with GridLayout
var count=e.getComponentCount();
var row=count/11;//for example, you have an 11*11 grid
var col=count%11;
var bb=new JButton(row+" "+col);//or any other text you like
bb.addActionListener(unused->System.out.println(
    "pressed button "+count+ " in row="+row+" col="+col
    ));
this.add(bb);