我有3个步骤的步骤形式。我希望<li>
中stepinstallment
的索引在<label>
内选中以进行检查:
如果选择了第一步,它将更改circle
类的背景颜色。
如果在没有第一步的情况下选择了第二步和第三步,则会显示错误消息。
我在SO上尝试了很多方法并自己写,但它不起作用。
这是我的代码
<ul class="clearfix">
<li>
<div class="step-one circle">
<p>Step 1</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 2</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 3</p>
</div>
</li>
</ul>
<div class="stepinstallment">
<ul>
<li id="step-one" class="step">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-two" class="step">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-three" class="step">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
</ul>
</div>
JS
var sCircle = $('.steps ul li');
$('.step label').on('click', function(){
var $this = $(this),
sCircleIndex = parseInt(sCircle.index()),
sCircleChild = sCircle.children('div'),
currParent = $this.parents('ul').index();
console.log(currParent);
});
以上JS代码始终返回0
。希望有人能把我弄清楚这个案子。提前谢谢。
答案 0 :(得分:1)
尝试使用.closest()
$(".stepinstallment label").on("click", function() {
console.log($(this).closest("li").index())
});
$('.stepinstallment label').on('click', function(){
console.log($(this).closest("li").index())
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<ul class="clearfix">
<li>
<div class="step-one circle">
<p>Step 1</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 2</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 3</p>
</div>
</li>
</ul>
<div class="stepinstallment">
<ul>
<li id="step-one">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-two">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-three">
<h2>Choose your document</h2>
<div class="step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" />
<span>ID card and household registration</span>
</label>
</div>
</li>
</ul>
</div>
答案 1 :(得分:1)
我希望这个例子可以帮助你!
$("ul#wizard li").click(function () {
var index = $("ul#wizard li").index(this);
if(index!=0)
alert("error ")
else
alert("index is: " + index)
});
&#13;
<ul id="wizard">
<li>Step 1</li>
<li>Step 2</li>
<li>Step 3</li>
<p>Some random tag</p>
</ul>
&#13;
答案 2 :(得分:0)
$('.step label')
不会返回任何元素,因为没有匹配css选择器的html
答案 3 :(得分:0)
我在你的HTML中看不到.steps
和.step
类。
使用你的html,我想这段代码可以正常工作
$('.stepinstallment').on('click', 'label', function (e) {
var $this = $(this);
var li = $this.parents('li');
console.log(li.index());
});
代码的步骤:
答案 4 :(得分:0)
标签上没有点击...它是空的。你可以绑定点击复选框,找到li的索引并在它的基础上为你的圈子中的LI的相同索引着色UL:
var sCircle = $('.steps ul li');
$('input[type=radio]').on('click', function(){
var liIndex=$(this).parents('li').index();
if(liIndex>0){
alert('error')
}
else{
$('ul.clearfix>li:eq('+liIndex+')').css('background-color','red')
}
});
答案 5 :(得分:0)
$(document).ready(function(){
var sCircle = $('.steps ul li');
$('.step label').on('click', function () {
var currentLi = $(this).parents('li')[0];
currentLiIndex = -1;
sCircle.each(function (index) {
if (sCircle[index] == currentLi) {
currentLiIndex = index;
}
});
console.log(currentLiIndex);
});
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul class="clearfix">
<li>
<div class="step-one circle">
<p>Step 1</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 2</p>
</div>
</li>
<li>
<div class="step-two circle">
<p>Step 3</p>
</div>
</li>
</ul>
<div class="stepinstallment steps">
<ul>
<li id="step-one">
<h2>Choose your document</h2>
<div class="step step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" /> <span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-two">
<h2>Choose your document</h2>
<div class=" step step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" /> <span>ID card and household registration</span>
</label>
</div>
</li>
<li id="step-three">
<h2>Choose your document</h2>
<div class="step step-content">
<label>
<input type="radio" id="option-1" name="options" value="1" /> <span>ID card and household registration</span>
</label>
</div>
</li>
</ul>
</div>
&#13;
答案 6 :(得分:0)
这是你需要做的。
$('.step-content label').on('click', function(){
var clickedId = $(this).parents('li').index();
if(clickedId == 0) {
$('.circle').css('background-color','yellow');
} else {
alert('error');
}
});
jsfiddle中的工作示例https://jsfiddle.net/1uxus551/