Question

我正在尝试使用以下查询获得结果，idRegion在数据库中记录为1,2,3,4为每个特许经营者，所以我想要显示所有特许经营者idRegion 2.我通过$ _Get获得idRegion 。这个显示只有昏迷前的第一个数字，我想它应该准备整个字符串1,2,3,4？当我使用有效的静态值时？

$colname_franchisee = "-1";
if (isset($_GET['id'])) {
  $colname_franchisee = $_GET['id'];
}


$query_franchisee = sprintf("SELECT * FROM franchise WHERE stiShowInLinks = 'Y' AND idRegion LIKE '%s%' ORDER BY stiName ASC", $colname_franchisee);

Answer 1

虽然我不喜欢你的数据库设计，但这应该可行：

$query_franchisee = sprintf("
    SELECT *
    FROM franchise
    WHERE
    stiShowInLinks = 'Y' AND (
        idRegion = '%d' OR
        idRegion LIKE '%d,%%' OR
        idRegion LIKE '%%,%d' OR
        idRegion LIKE '%%,%d,%%'
    )
    ORDER BY stiName ASC
",
$colname_franchisee,
$colname_franchisee,
$colname_franchisee,
$colname_franchisee
);

sprintf函数将%字符视为格式说明符，并以特殊方式处理接下来的几个字符。要按字面意思使用%字符，您必须使用%%。因此，在sprintf之后，您的查询变为：

idRegion = '1234' OR
idRegion LIKE '1234,%' OR
idRegion LIKE '%,1234' OR
idRegion LIKE '%,1234,%'

Answer 2

$colname_franchisee = "-1";
if (isset($_GET['id'])) {
  $cf = intval($_GET['id']);  only if id integer.

}
$query_franchisee = "SELECT * FROM franchise 
                     WHERE stiShowInLinks = 'Y' 
                       AND idRegion LIKE '%cf%' 
                     ORDER BY stiName ASC", $cf);

mysql查询中的动态值

2 个答案: