Question

SELECT a.id, a.username, a.email, a.created, b.user_id, 
    SUM( (b.price >500) +100 ) + SUM( b.price ) AS gr, SUM( b.price ) AS pris,
     b.created, c.user_id, c.referrer_id, c.created, d.id, d.beginner, d.winner_id
FROM users a, accounts b, referrals c, product d
WHERE a.created
BETWEEN  '2013-05-01'
AND  '2013-05-31'
AND a.id = b.user_id
AND a.id = c.user_id
AND d.beginner !=  '1'
AND d.winner_id = a.id
GROUP BY c.referrer_id
ORDER BY  `pris` ASC 
LIMIT 0 , 3

我已经制定了这个查询。我想解决的问题是

SUM(( b.price >500) +100) + SUM( b.price ) AS gr

我想要计算，如果一个ID的总价格在一个月内超过500，那么它就会增加100.我不确切地知道如何计算此查询中一个人的总价并添加100如果一个月内计数超过500？

Answer 1

您可以在此使用CASE声明

SUM( CASE WHEN b.price >500 THEN b.price+100 ELSE b.price END) as gr

Answer 2

在您的查询中尝试此操作。

SUM(if(b.price >500,100,0))

Answer 3

糟糕。只是重新阅读你的问题。

一个身份证的总价格：

sum(b.price)

测试一个ID的总价格是否> 500，如果超过500，则加100：

sum(b.price) + case when sum(b.price) >500 then 100 else 0 end as gr

查询内部的计算

3 个答案: