Question

你如何从更大的2d列表中获得2d子列表？

gridx = 10
gridy = 16

grid = [[0]*gridx for i in range(gridy)]
subgrid = None
# I want to get a subgrid given an x,y grid origin (bottom-left) and x,y subgrid size

Answer 1

如果你想在极限x1，y1，x2，y2切片你的2D列表，你可以这样做：

def getsubgrid(x1, y1, x2, y2, grid):
    return [item[x1:x2] for item in grid[y1:y2]]

例如：

grid = [[1, 2, 3, 4, 5, 6, 7, 8, 9],
        [11,12,13,14,15,16,17,18,19],
        [21,22,23,24,25,26,27,28,29],
        [31,32,33,34,35,36,37,38,39],
        [41,42,43,44,45,46,47,48,49],
        [51,52,53,54,55,56,57,58,59]]

print getsubgrid(3,2,5,4,grid)

#prints [[24, 25], [34, 35]]

Answer 2

我假设您的网格存储在列表列表中？那就是：

primary list: [ * * * * * * ]
second item:    * * * * * *

如果是这样，您的答案就是从起点到终点遍历这些列表。

sublist = []
for x in range(startx, endx):
     sublist.append(oldlist[x][starty:endy])

Python从更大的2d列表中获得“sub”2d列表？

2 个答案: