Question

为什么这个循环在输入数字时执行3次？我只想要's'或'm'被接受..我怎么能解决这个问题？

cout << "Are you married or single (m/s): ";
    cin >> status;
    status = tolower(status); //converting to lower case

    //validating imput for marital status
    while((status != 'm') && (status != 's'))
    {
         cout << "Sorry, you must enter \"m\" or \"s\" \n"
              << "Are you married or single (m/s): ";
         cin >> status;
         status = tolower(status);
    }

Answer 1

您的变量status可能声明为：

char status;

因此，cin >> status从输入中读取单个字符。但是，您可能键入了多个，因为输入已缓冲，您需要按Enter键。

相反，请使用此声明：

string status;

将获得整行输入，然后您可以检查行内的字符。

Answer 2

您可以使用getchar()保存到状态，它只从缓冲区中读取一个字符..

    cout << "Are you married or single (m/s): ";
    getchar(status);

    //validating imput for marital status
    while((status != 'm') || (status != 's'))    //status can be a male OR a female
    {
         cout << "Sorry, you must enter \"m\" or \"s\" \n"
              << "Are you married or single (m/s): ";
    getchar(status);
    }

输入数字时出现循环错误

2 个答案: