Question

我有两张桌子：

Employee:
    ID
    SalaryPerDay
    overTimeHoursPrice
    .....
    .....

Schedule:
    ID
    EmployeeID
    Date
    Attending  (boolean)
    loan
    discount
    overTimeHours

有多对一的关系

我想要一个返回的查询

[员工姓名]和

[sum（loan）]和

[sum（discount）]和

[sum（overTimeHours）]和

[count（参加）]参加= true和

[count（参加）* SalaryPerDay]和

[sum（overTimeHours）* overTimeHoursPrice]和

[（计数（参加）* SalaryPerDay）+（sum（overTimeHours）* overTimeHoursPrice） - （总和（折扣）） - （总和（贷款））]

1-其中Date＆gt; = [date1]和Date＆lt; = [date2]

2-其中Date＆gt; = [date1]和Date＆lt; = [date2]和EmployeeName = [name]

（date1和date2以及名称是参数）

Answer 1

这样的事情可以解决这个问题......

SELECT 
  emp.EmployeeName, sum_loan, sum_discount, sum_overTimeHours, count_attending, 
  (count_attending*SalaryPerDay) as totalDayPay,
  (sum_overTimeHours*overTimeHoursPrice) as totalOverTimePay,
  ((count_attending*SalaryPerDay) + (sum_overTimeHours*overTimeHoursPrice) -
    sum_discount - sum_loan) as grandTotal
FROM Employee emp
  INNER JOIN (SELECT
      EmployeeID,
      sum(loan) as sum_loan,
      sum(discount) as sum_discount,
      sum(overTimeHours) as sum_overTimeHours,
      sum(iif(Attending,1,0)) as count_attending
    FROM Schedule
    WHERE Date >= {date1} and Date <= {date2}
    GROUP BY EmployeeID
  ) sch
  ON emp.ID = sch.EmployeeID
WHERE emp.EmployeeName = {name}

请注意两个WHERE子句。您可以根据需要调整这些以实现两个不同的参数化限制。

编辑＃1：
由于存储在Schedule.Attending字段中的“布尔”的实际数值存在一些不确定性，我调整了上面的查询以明确地考虑布尔值。为此，我使用了特定于MSAccess的表达式函数IIF()。这是一个更强大的解决方案，而不仅仅是假设该字段包含1或0。

编辑＃2： 我还应该注意，语法会略有不同，具体取决于您使用它的位置。以上是派生表的“标准sql”语法（即INNER JOIN个关键字后括号内的子查询）。如果您通过ODBC连接运行此查询，则上述语法有效。

但是，如果您尝试在Access中创建查询，则需要在子查询周围使用带有尾随句点[ ].而不是括号( )的方括号。所以而不是：

SELECT ... FROM Employee emp INNER JOIN (SELECT ... ) sch ON ...

使用它：

SELECT ... FROM Employee emp INNER JOIN [SELECT ... ]. sch ON ...

Answer 2

我想你想要：

SELECT e.EmployeeName, 
   Sum(s.loan) AS SumOfloan, 
   Sum(s.discount) AS SumOfdiscount, 
   Sum(s.overTimeHours) AS SumOfoverTimeHours, 
   Sum(Abs([Attending])) AS Attnd, 
   Sum([SalaryPerDay]*Abs([Attending])) AS SalyAttnd, 
   Sum([overTimeHoursPrice]*[overtimehours]) AS OTCost, 
   Sum(([SalaryPerDay]*Abs([Attending])+[overTimeHoursPrice]*[overtimehours])-([loan]-[discount])) AS Due
FROM Employee e
INNER JOIN Schedule s ON e.ID = s.EmployeeID
WHERE s.Date Between [date1] And [Date2]
AND EmployeeName = [Name] 
GROUP BY e.ID, e.EmployeeName

请注意，布尔值为0或-1，因此[SalaryPerDay] * Abs（[Attending] = Salary * 1，如果参加或0，如果不参加。

在microsoft访问下的Sql Query语句

2 个答案: