SELECT
Item.Itemno
, SUM(Delivered_item.qtyordered) AS SumOfqtyordered
, SUM(Item_issued.qtyissued) AS SumOfqtyissued
FROM
Item
INNER JOIN Delivered_item ON Item.Itemno = Delivered_item.itemno
INNER JOIN Item_issued ON Item.Itemno = Item_issued.Itemno
GROUP BY
Item.Itemno;
这是我的sql视图。在我的数据库中,delivered_item
有7条记录,而item_issued
只有2条记录。当我执行SUM
时,qtyissued
的总数出错,1条记录(qtyissued
)乘以3而另一条记录乘以4,因为delivered_item
有7条记录(2个相同itemno
)...如何解决这个问题...
答案 0 :(得分:0)
您需要使用子查询:
SELECT *
FROM item i
INNER JOIN
(SELECT itemno,
Sum(qtyordered)
FROM delivereditem
GROUP BY itemno) d ON d.itemno = i.itemno
INNER JOIN
(SELECT itemno,
Sum(qtyissued)
FROM itemissued
GROUP BY itemno) iss ON iss.itemno = i.itemno
如果您认为可能需要执行此操作,请将每个子查询转换为视图并使用该子查询(保存打字时)
编辑:在子查询中添加了分组。对不起!