Question

我在数据库表的一行中插入了几个（array）值和json_encode的值，现在希望用jquery将它们作为顺序回显。

这是我的PHP代码输出：

[{
    "guide": null,
    "residence": [{
        "name_r": "jack"
    }, {
        "name_r": "jim"
    }, {
        "name_r": "sara"
    }],
    "residence_u": [{
        "units": ["hello", "how", "what"],
        "extra": ["11", "22", "33"],
        "price": ["1,111,111", "2,222,222", "3,333,333"]
    }, {
        "units": ["fine"],
        "extra": ["44"],
        "price": ["4,444,444"]
    }, {
        "units": ["thanks", "good"],
        "extra": ["55", "66"],
        "price": ["5,555,555", "6,666,666"]
    }]
}]

我想作为（输出）：

jack
hello＆amp; 11＆amp; 1,111,111
how＆amp; 22＆amp; 2,222,222
what＆amp; 33 ＆安培; 3,333,333,

jim
fine＆amp; 44＆amp; 4,444,444

sara
thanks＆amp; 55＆amp; 5,555,555
good＆amp; 66＆amp; 6,666,666

怎么回事？

Answer 1

假设

您已经知道如何使用PHP脚本获取此信息的ajax请求
顶层数组中总有一个元素（如果没有，你可以再增加一个迭代级别）
按输出你的意思是访问相应的元素 - 我已经调用了console.log但你可以alert()或者放入DOM元素或其他什么

你可以在jQuery中做这样的事情（这里是没有网络部分的example fiddle。你会在你的控制台中看到输出）

var data = response[0]; //response is the data received by the jQuery ajax success callback
var residences = data.residence;
var residence_u = data.residence_u;

$.each(residences, function(index, val){
    var name = val.name_r;
    console.log(name);

    var info = residence_u[index]; //get the corresponding residence_u element

    $.each(info.units, function(index, val){
        var unit = val;
        var extra = info.extra[index];
        var price = info.price[index];
        console.log( val + " & " + extra + " & " + price);
    });
});

使用jQuery从json_encode获取值

1 个答案: