Question

如何让两个数组相互对应？

例如，这是我生成的第一个月数组，

Array
(
    [0] => Sep
    [1] => Oct
    [2] => Nov
    [3] => Dec
    [4] => Jan
    [5] => Feb
    [6] => Mar
    [7] => Apr
    [8] => May
    [9] => Jun
    [10] => Jul
    [11] => Aug
)

这是第二个月的数组，

Array
(
    [0] => Sep
    [1] => May
    [2] => Apr
)

但我希望第二个月的数组遵循与第一个月数组相同的顺序，以此作为结果返回

Array
(
    [0] => Sep
    [1] => Apr
    [2] => May
)

有可能吗？

修改

我用来生成上面的月份数组的代码，

# Set month array for the calendar and for the items.
$months_calender = array();
$months_items = array();

# Set variable for requested month/year.
$requested_year = set_variable($_REQUEST,'year');
$requested_month = set_variable($_REQUEST,'month');

# Set current month and curren year.
$current_month = (int)date('m');
$current_year = (int)date('Y');

# Loop the 12 month and starts from the current month.
for($x = $current_month; $x < $current_month+12; $x++) $months_calender[] = date('M', mktime(0, 0, 0, $x, 1));
print_r($months_calender); 
//echo $current_year;

# Check if the requested by $_REQUEST does not exit then use the current month/year as the requested month/year.
$requested_year = $requested_year? $requested_year : $current_year;
$requested_month = $requested_month? $requested_month : date('m', mktime(0, 0, 0, $current_month, 1));
//var_dump($requested_year);
//echo $requested_month;

# Use the stored connection object from the class_page_controller.php, to process the query
$items_monthly = $connection->fetch_all($sql_items_monthly,array($requested_year));
$total_items_monthly = $connection->num_rows($sql_items_monthly,array($requested_year));
//print_r($items_monthly);

# Check if the total items is more than 0, then loop the result to make an 1-d array.
if($total_items_monthly > 0) foreach($items_monthly as $item_monthly) $months_items[] = $item_monthly['archiveMonth'];
print_r($months_items);

sql，

$sql_items_monthly = "
    SELECT 
    DATE_FORMAT(p.pg_backdate, '%b') AS archiveMonth,
    COUNT(p.pg_backdate)

    FROM root_pages AS p
    WHERE DATE_FORMAT(p.pg_backdate, '%Y') = ?
    AND p.cat_id = '2'
    AND p.parent_id = '6'
    AND p.pg_hide != '1'

    GROUP BY archiveMonth
    ORDER BY p.pg_backdate DESC
";

修改

看来我可以得到这个结果，

$result = array_intersect($months_calender, $months_items);
print_r($result);

返回，

Array
(
    [0] => Sep
    [7] => Apr
    [8] => May
)

即使keys没有从0到2开始，但也没关系。除非你有更好的解决方案。

Answer 1

array_intersect和ksort的简单组合可以解决问题：

$array2 = array_intersect($array1, $array2);
ksort($array2);

<强> See it in action

如果由于某种原因你想在此之后有连续的整数键，那么重新索引生成的数组也很容易：

$array2 = array_values($array2);

Answer 2

uksort似乎提供了一种可能性：http://php.net/manual/en/function.uksort.php

它允许您使用自己的排序功能定义如何对数组进行排序。您可以使用自定义函数对数组执行每个键的搜索，然后按索引对它们进行排序。

Answer 3

使用array_intersect();

/**
 * @var array $all All months in the correct order
 * @var array $selected Selected months in any order
 */
$result = array_intersect($all, $selected);

编辑：我刚看完你的编辑，发现你得到了相同的答案。要解决索引问题，只需将结果包装在array_values();

中

$result = array_values(array_intersect($all, $selected));

如何使两个数组与PHP相互对应？

3 个答案: