Question

我有两个成员数相同的数组（总是）$userInputArr=array("z","z","E","z","z","E","E","E","E","E");和$user2InputArr=array("a","a","a","z","a","E","E","E","a","E");我知道如何在两个数组中找到匹配的成员。在这里，我想找到具有相似索引的匹配元素，例如if $ userInputArr [4] == $ user2InputArr [4]，增加$ matches。在我下面的尝试中，我遍历两个数组，但我不能让$ matchs增加。

$match = 0;
for ($c =0; $c < count($$userInputArr); $c++) {
    for ($d = $c; $d<count($user2InputArr);$d++) {
        if ($userAnsStrArr[$c] == $userInputArr[$d]) {
            $match = $match +1;
        }
    }
}

Answer 1

这个问题是PHP函数array_intersect_assoc()的完美示例：

$array1 = array("z","z","E","z","z","E","E","E","E","E");
$array2 = array("a","a","a","z","a","E","E","E","a","E");

// Find the matching pairs (key, value) in the two arrays
$common = array_intersect_assoc($array1, $array2);
// Print them for verification
print_r($common);

// Count them
$match = count($common);
echo($match." common items.\n");

输出结果为：

Array
(
    [3] => z
    [5] => E
    [6] => E
    [7] => E
    [9] => E
)
5 common items.

Answer 2

$match = 0;
for ($c =0; $c < count($$userInputArr); $c++) {

    if ($userAnsStrArr[$c] == $userInputArr[$c]) {
            $match = $match +1;
        }

}

你应该这样做。

Answer 3

这对我有用

$i = sizeof($userInputArr);

 $match = 0;
for($j = 0; $j < $i; $j++)
    if ($userInputArr[$j] == $user2InputArr[$j]) {
        $match = $match +1;
    }

Answer 4

这是给你的代码。只需使用一个foreach，遍历第一个array，然后检查第二个key-value中的array。

$s = array("z","z","E","z","z","E","E","E","E","E"); 
$b = array("a","a","a","z","a","E","E","E","a","E");

foreach($s as $k => $v) {
    if($b[$k] === $s[$k]) {
        echo $k . ' is the index where keys and values exactly match with value as ' . $b[$k];
    }
}

输出：

3 is the index where keys and values exactly match with value as z
5 is the index where keys and values exactly match with value as E
6 is the index where keys and values exactly match with value as E
7 is the index where keys and values exactly match with value as E
9 is the index where keys and values exactly match with value as E

这是链接：https://3v4l.org/eX0r4

Answer 5

我似乎你的代码在单循环中不需要两个for循环增加匹配，见下面的代码。

<?php
$userInputArr=array("z","z","E","z","z","E","E","E","E","E");
$user2InputArr=array("a","a","a","z","a","E","E","E","a","E");
$match = 0;
for ($c =0; $c < count($userInputArr); $c++) {
    if ($user2InputArr[$c] == $userInputArr[$c]) {
        $match = $match + 1;
    }
}
echo $match;
?>

比较两个数组元素，在相似的索引中相互比较

5 个答案: