Question

我想做一些类似“Where conditions ='$ condition'或条件='$ condition2'或条件='$ condition3'但会返回数据库中的所有条目与我正在寻找的条目..我是什么我可以做到这一点吗？

$sql = "SELECT STRAIGHT_JOIN DISTINCT table1.person_id, table1.full_name, 
table2.stuff_id, table2.stuff_name, table3.whatever_why, 
table3.whatever_comments, table3.whatever_test_id
from table1 
join table4 on table1.person_id = table4.person_id 
join table2 on table4.stuff_id  = table2.stuff_id
join table3 on table1.person_id = table3.person_id 
WHERE conditions = '$condition' and ( (
     table3.whatever_why like '%$q%'
  OR table3.whatever_comments like '%$q%'
  OR table3.whatever_name like '%$q%'
))
order by table3.id DESC limit $startrow, 10";

$result = mysql_query($sql);

Answer 1

您可以使用括号对逻辑进行分组。

继续列出OR语句将匹配行，如果其中任何一行为真。

Answer 2

Where conditions in ('$condition1', '$condition2', '$condition3')

如何在Where语句中多次使用OR？

2 个答案: