Question

我需要结合3个求和查询的结果并在循环中回显结果。我坚持认为这是如何以正确的方式完成的。我想使用while循环为每个客户端回显一行，显示按客户端名称分组的3个求和查询的结果：

客户名称|总到期|现金销售总额|信贷销售总额

结果显示所有由于客户端。 noncashresult显示所有由于来自Credit销售的客户。 cashresult显示全部由于来自现金销售的客户。

$result = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Total Due` 
FROM `Consignment` 
WHERE `payout_approved` = 'Yes' 
GROUP BY `client_name`"); 

$noncashresult = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Credit Total Due`
FROM `Consignment` 
WHERE `payout_approved` = 'Yes' AND `paymenttype` IN ('Credit') 
GROUP BY `client_name`");

$cashresult = mysql_query("SELECT `client_name` As `Client`, SUM(`due_to_client`) As `Cash Total Due`
FROM `Consignment` 
WHERE `payout_approved` = 'Yes' AND `paymenttype` IN ('Cash') 
GROUP BY `client_name`");

while($row = mysql_fetch_array($result))
                    {
                echo $row['Client'];
                echo $row['Total Due'];
                echo $row['Credit Total Due'];
                echo $row['Cash Total Due'];
                    }

Answer 1

您可以使用以下内容：

SELECT `client_name` As `Client`,
SUM(`due_to_client`) As `Total Due`,
SUM(CASE WHEN `paymenttype`='Credit' THEN `due_to_client` ELSE 0 END) As `Credit Total Due`,
SUM(CASE WHEN `paymenttype`='Cash' THEN `due_to_client` ELSE 0 END) As `Cash Total Due`
FROM `Consignment` 
WHERE `payout_approved` = 'Yes' 
GROUP BY `client_name`

这应该产生结果：

Client | Total Due | Credit Total Due | Cash Total Due

当然，尽量避免使用mysql_ *扩展，而在mysql 5.5.x中不推荐使用它。而是使用mysqli或pdo扩展

使用Union或Join在where语句中使用多个查询结果

1 个答案: