考虑此查询:
SELECT [Order Details].OrderID,
c.CategoryName,
COUNT(c.CategoryID)
FROM [Order Details]
INNER JOIN Products p
ON p.ProductID = [Order Details].ProductID
INNER JOIN Categories c
ON c.CategoryID = p.CategoryID
GROUP BY
[Order Details].OrderID,
c.CategoryName
ORDER BY
[Order Details].OrderID
此查询返回此结果(Usnig Northwind数据库):
我想使用Pivot with Join来获得这样的结果:
OrderID Condiments Produce Seafood Condiments Grains/Cereals ...
--------------------------------------------------------------------------------------
10250 1 1 1 0 0 ...
10251 1 0 0 0 2 ...
...
我怎么能这样做?
由于
答案 0 :(得分:5)
WITH T
AS (SELECT [Order Details].OrderID,
c.CategoryName,
c.CategoryID
FROM [Order Details]
INNER JOIN Products p
ON p.ProductID = [Order Details].ProductID
INNER JOIN Categories c
ON c.CategoryID = p.CategoryID)
SELECT *
FROM T PIVOT ( COUNT (CategoryID) FOR CategoryName IN (
[Beverages],
[Condiments],
[Confections],
[Dairy Products],
[Grains/Cereals],
[Meat/Poultry],
[Produce],
[Seafood]) ) AS pvt
ORDER BY OrderID