Question

这是表'VendorItemPricing'。

ItemID  VendorName     VendorPrice    
122     HP             215.13
122     IBM            264.41
122     Microsoft      257.65

我使用此查询将行设为列。

Select ItemID,
[HP] As HPPrice ,
[Apple] As ApplePrice,
[Microsoft] As MicrosoftPrice,
[IBM] As IBMPrice from (
select ItemID,VendorName,VendorPrice from VendorItemPricing where ItemID = 122)A
PIVOT(MAX(VendorPrice) FOR VendorName IN ([HP],[Apple],Microsoft,IBM))P

这就是我预期的输出。

ItemID  HPPrice  ApplePrice  MicrosoftPrice  IBMPrice
122     215.13   NULL        257.65          264.41

这是我的表'MasterItems'，我使用此查询得到以下结果。

select ItemID, ItemPartNumber, ItemDescription, CreatedDate, InitialPrice from MasterItems where ItemID = 122

这可能是结果。

ItemID  ItemPartNumber  ItemDescription  CreatedDate                InitialPrice
122     AB246VB         Volt Fuser Kit   2015-05-15 17:17:32.940    215.14

是否可以加入两个结果并获得如下结果？

ItemID  ItemPartNumber  ItemDescription  CreatedDate                InitialPrice    HPPrice    ApplePrice   MicrosoftPrice   IBMPrice
122     AB246VB         Volt Fuser Kit   2015-05-15 17:17:32.940    215.14          215.13     NULL         257.65           264.41

Answer 1

您只需在PIVOT：

的源表中执行连接即可

Select ItemID, ItemPartNumber, ItemDescription, CreatedDate, InitialPrice,
       [HP] As HPPrice, 
       [Apple] As ApplePrice, 
       [Microsoft] As MicrosoftPrice,
       [IBM] As IBMPrice 
from (
   select v.ItemID, VendorName, VendorPrice, 
          ItemPartNumber, ItemDescription, CreatedDate, InitialPrice
   from VendorItemPricing as v 
   left join MasterItems as m on v.ItemID = m.ItemID
   where v.ItemID = 122)A
PIVOT(
   MAX(VendorPrice) 
   FOR VendorName IN ([HP],[Apple],Microsoft,IBM)
)P

SQL Fiddle Demo

Answer 2

假设使用样本数据，如您所说主表使用CTE加入枢轴集结果

declare  @table  table (Itemid Int,Vendorname varchar(10),VendorPrice DECIMAL(18,2))
insert into @table (Itemid,Vendorname,VendorPrice)
values (122,'HP',125.66),
(122,'microsoft',134.00),
(122,'IBM',124.90)

Declare @master table (Itemid int,Partnumber Varchar(10),Description varchar(20),Created datetime,InitialPrice decimal(18,2))
insert into @master (Itemid,Partnumber,Description,Created,InitialPrice)values (122,'AB246VB','Volt Fuser Kit',GETDATE(),215.14)

;with cte as (
Select Itemid,[HP] As HPPrice ,
[Apple] As ApplePrice,
[microsoft] As microsoftPrice,
[IBM] As IBMPrice from (
select Itemid,Vendorname,VendorPrice from @table where ItemID = 122)A
PIVOT(MAX(VendorPrice) FOR Vendorname IN ([HP],[Apple],[microsoft],[IBM]))P)
select t.Itemid,
t.Partnumber,
t.Description,
t.Created,
t.InitialPrice,
c.HPPrice,c.ApplePrice,
c.IBMPrice,
c.microsoftPrice from  @master t,cte c where t.ItemID = 122

Answer 3

SELECT M.*, [HP] As HPPrice, 
       [Apple] As ApplePrice, 
       [Microsoft] As MicrosoftPrice,
       [IBM] As IBMPrice
FROM MasterItems M
JOIN (
    select ItemID,VendorName,VendorPrice from VendorItemPricing where ItemID = 122
)A
PIVOT(MAX(VendorPrice) FOR VendorName IN ([HP],[Apple],Microsoft,IBM)) P
ON M.ItemId = P.ItemId

您可以根据需要将JOIN调整为LEFT JOIN。

如何在SQL Server中一起使用PIVOT和JOIN？

3 个答案: