多列的平均值

Question

我有一个名为Request的表，数据如下：

Req_ID    R1   R2   R3   R4   R5

R12673    2    5    3    7    10
R34721    3    5    2    1    8
R27835    1    3    8    5    6

现在我想显示R1，R2，R3，R4和R5

的平均值

所以我写了一个像：

这样的查询

Select Req_ID, Avg(R1+R2+R3+R4+R5) as Average
from Request
Group by Req_ID

但我只得到R1，R2，R3，R4和R5的总和不是平均值？我在哪里做错了。

Answer 1

您没有提到列是否可以为空。如果它们是，并且您想要AVG聚合提供的相同语义（2008）

SELECT *,
       (SELECT AVG(c)
        FROM   (VALUES(R1),
                      (R2),
                      (R3),
                      (R4),
                      (R5)) T (c)) AS [Average]
FROM   Request  

2005版本有点单调乏味

SELECT *,
       (SELECT AVG(c)
        FROM   (SELECT R1
                UNION ALL
                SELECT R2
                UNION ALL
                SELECT R3
                UNION ALL
                SELECT R4
                UNION ALL
                SELECT R5) T (c)) AS [Average]
FROM   Request

Answer 2

如果数据存储为INT，您可能需要尝试

Average = (R1 + R2 + R3 + R4 + R5) / 5.0

Answer 3

你可以这样做：

Select Req_ID, (avg(R1)+avg(R2)+avg(R3)+avg(R4)+avg(R5))/5 as Average
from Request
Group by Req_ID

右？

我假设您可能有多个具有相同Req_ID的行，在这些情况下，您希望计算具有相同Req_ID的那些行的所有列和行的平均值

Answer 4

在PostgreSQL中，要获得一行中多个（2到8）列的平均值，只需定义一组七个函数，称为average（）。将产生非空列的平均值。

然后只是

select *,(r1+r2+r3+r4+r5)/5.0,average(r1,r2,r3,r4,r5) from request;
 req_id | r1 | r2 | r3 | r4 | r5 |      ?column?      |      average
--------+----+----+----+----+----+--------------------+--------------------
 R12673 |  2 |  5 |  3 |  7 | 10 | 5.4000000000000000 | 5.4000000000000000
 R34721 |  3 |  5 |  2 |  1 |  8 | 3.8000000000000000 | 3.8000000000000000
 R27835 |  1 |  3 |  8 |  5 |  6 | 4.6000000000000000 | 4.6000000000000000
(3 rows)

update request set r4=NULL where req_id='R34721';
UPDATE 1

select *,(r1+r2+r3+r4+r5)/5.0,average(r1,r2,r3,r4,r5) from request;
 req_id | r1 | r2 | r3 | r4 | r5 |      ?column?      |      average
--------+----+----+----+----+----+--------------------+--------------------
 R12673 |  2 |  5 |  3 |  7 | 10 | 5.4000000000000000 | 5.4000000000000000
 R34721 |  3 |  5 |  2 |    |  8 |                    | 4.5000000000000000
 R27835 |  1 |  3 |  8 |  5 |  6 | 4.6000000000000000 | 4.6000000000000000
(3 rows)

select *,(r3+r4+r5)/3.0,average(r3,r4,r5) from request;
 req_id | r1 | r2 | r3 | r4 | r5 |      ?column?      |      average
--------+----+----+----+----+----+--------------------+--------------------
 R12673 |  2 |  5 |  3 |  7 | 10 | 6.6666666666666667 | 6.6666666666666667
 R34721 |  3 |  5 |  2 |    |  8 |                    | 5.0000000000000000
 R27835 |  1 |  3 |  8 |  5 |  6 | 6.3333333333333333 | 6.3333333333333333
(3 rows)

像这样：

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC,
V4 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    IF V4 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V4; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC,
V4 NUMERIC,
V5 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    IF V4 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V4; END IF;
    IF V5 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V5; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC,
V4 NUMERIC,
V5 NUMERIC,
V6 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    IF V4 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V4; END IF;
    IF V5 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V5; END IF;
    IF V6 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V6; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC,
V4 NUMERIC,
V5 NUMERIC,
V6 NUMERIC,
V7 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    IF V4 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V4; END IF;
    IF V5 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V5; END IF;
    IF V6 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V6; END IF;
    IF V7 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V7; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

CREATE OR REPLACE FUNCTION AVERAGE (
V1 NUMERIC,
V2 NUMERIC,
V3 NUMERIC,
V4 NUMERIC,
V5 NUMERIC,
V6 NUMERIC,
V7 NUMERIC,
V8 NUMERIC)
RETURNS NUMERIC
AS $FUNCTION$
DECLARE
    COUNT NUMERIC;
    TOTAL NUMERIC;
BEGIN
    COUNT=0;
    TOTAL=0;
    IF V1 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V1; END IF;
    IF V2 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V2; END IF;
    IF V3 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V3; END IF;
    IF V4 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V4; END IF;
    IF V5 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V5; END IF;
    IF V6 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V6; END IF;
    IF V7 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V7; END IF;
    IF V8 IS NOT NULL THEN COUNT=COUNT+1; TOTAL=TOTAL+V8; END IF;
    RETURN TOTAL/COUNT;
    EXCEPTION WHEN DIVISION_BY_ZERO THEN RETURN NULL;
END
$FUNCTION$ LANGUAGE PLPGSQL;

Answer 5

这适用于 MariaDB：

SELECT Req_ID, (R1+R2+R3+R4+R5)/5 AS Average
FROM Request
GROUP BY Req_ID;

Answer 6

如果有人正在寻找同时列出的多列的平均值，例如

你可以像SELECT AVG(SurfaceArea), AVG(Population) FROM country

你可以像SELECT AVG(SurfaceArea) AS value1, AVG(Population) as value2 FROM country

Answer 7

Select Req_ID, sum(R1+R2+R3+R4+R5)/5 as Average
from Request
Group by Req_ID;