按指定顺序递增数字

时间：2011-09-09 07:17:36

标签： java

我需要通过递增生成一系列数字。对于Ex，如果从001开始直到999，则不应该再次A01，直到A99接下来应该是B01。任何人都可以帮我写一个逻辑。应该使用Java代码实现。

7 个答案:

答案 0 :(得分：1)

一次分配一批100个数字并使用它们，并在现有批次耗尽时分配新批次。所以像String getBatchPrefix（）生成0，“A”，“B”...然后创建一个对象

class BatchIncrementer {
   private final String prefix;  
   private final AtomicInteger incrementer;

   BatchIncrementer(String pPrefix) {
       incrementer = new AtomicInteger();
       prefix = pPrefix;
   }
   Integer getNext() {
      return incementer.getAndIncrement();
   }
   Boolean hasNext() {
      return incrementer.get() < 100;
   }
}

答案 1 :(得分：1)

简单且未完成，

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class GenerateProgresId {

    private static String[] aChar = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J",
        "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"};
    private static List<String> listA;

    public GenerateProgresId() {
        List<Number> list3 = new ArrayList<Number>();
        List<Integer> list4 = new ArrayList<Integer>();
        List<? extends Number> list5 = new ArrayList<Integer>();
        List<? extends Number> list6 = list4;
        list3.add(Integer.valueOf(333));
        list4.add(Integer.valueOf(444));
        //list5.add(Integer.valueOf(555)); // compile error
        //list6.add(Integer.valueOf(666)); // compile error
        Number n3 = list3.get(0);
        Integer i4 = list4.get(0);
        Number n5 = !list5.isEmpty() ? list5.get(0) : null;
        Number n6 = list6.get(0);
        System.out.printf("%s, %s, %s, %s%n", n3, i4, n5, n6);
        int pomocInt = 1;
        String pomocStr = "";
        if (pomocInt < 10) {
            pomocStr = "0" + pomocInt;
        } else if (pomocInt < 100) {
            pomocStr = String.valueOf(pomocInt);
        } else {
            pomocStr = String.valueOf(pomocInt);
        }
        System.out.println(pomocStr);
        pomocInt = 12;
        pomocStr = "";
        if (pomocInt < 10) {
            pomocStr = "0" + pomocInt;
        } else if (pomocInt < 100) {
            pomocStr = String.valueOf(pomocInt);
        } else {
            pomocStr = String.valueOf(pomocInt);
        }
        System.out.println(pomocStr);
        pomocInt = 157;
        pomocStr = "";
        if (pomocInt < 10) {
            pomocStr = "0" + pomocInt;
        } else if (pomocInt < 100) {
            pomocStr = String.valueOf(pomocInt);
        } else if (pomocInt > 99) {
            pomocStr = String.valueOf(pomocInt);
            pomocStr = pomocStr.substring(pomocStr.length() - 2, pomocStr.length());
        }
        System.out.println(pomocStr);
        listA = new ArrayList<String>();
        listA.addAll(Arrays.asList(aChar));
        System.out.println("From List");
        System.out.println(GenerateProgresIdList(null));
        System.out.println(GenerateProgresIdList(""));
        System.out.println(GenerateProgresIdList("B"));
        System.out.println(GenerateProgresIdList("AA"));
        System.out.println(GenerateProgresIdList("AZ"));
        System.out.println(GenerateProgresIdList("ZY"));
        System.out.println(GenerateProgresIdList("ZZ"));
        System.out.println("From String[]");
        System.out.println(GenerateProgresIdString(null));
        System.out.println(GenerateProgresIdString(""));
        System.out.println(GenerateProgresIdString("B"));
        System.out.println(GenerateProgresIdString("AA"));
        System.out.println(GenerateProgresIdString("AZ"));
        System.out.println(GenerateProgresIdString("ZY"));
        System.out.println(GenerateProgresIdString("ZZ"));
    }

    public static String GenerateProgresIdList(String str) {
        int lastChar = aChar.length - 1;
        String retStr = "AA";
        if (str != null) {
            if (str.length() > 0) {
                if (str.length() == 1) {
                    retStr = str + aChar[0];
                } else if (str.length() == 2) {
                    int stChar = listA.indexOf(str.substring(0, 1));
                    int ndChar = listA.indexOf(str.substring(1, str.length()));
                    if ((stChar != lastChar) || (ndChar != lastChar)) {
                        if (ndChar == lastChar) {
                            retStr = listA.get(stChar + 1) + listA.get(0);
                        } else {
                            retStr = listA.get(stChar) + listA.get(ndChar + 1);
                        }
                    }
                }
            }
        }
        return retStr;
    }

    public static String GenerateProgresIdString(String str) {
        String lastChar = aChar[aChar.length - 1];
        String retStr = "AA";
        if (str != null) {
            if (str.length() > 0) {
                if (str.length() == 1) {
                    retStr = str + aChar[0];
                } else if (str.length() == 2) {
                    if ((!str.substring(0, 1).equals(lastChar)) || (!str.substring(1, str.length()).equals(lastChar))) {
                        String pos1 = str.substring(0, 1);
                        String pos2 = str.substring(1, str.length());
                        if ((pos2).equals(lastChar)) {
                            int heplInt = 0;
                            for (int i = 0; i < aChar.length; i++) {
                                if (aChar[i].equals(pos1)) {
                                    heplInt = i + 1;
                                    break;
                                }
                            }
                            retStr = aChar[heplInt] + aChar[0];
                        } else {
                            int heplInt = 0;
                            for (int i = 0; i < aChar.length; i++) {
                                if (aChar[i].equals(pos2)) {
                                    heplInt = i + 1;
                                    break;
                                }
                            }
                            retStr = pos1 + aChar[heplInt];
                        }
                    }
                }
            }
        }
        return retStr;
    }

    public static void main(String[] args) {
        GenerateProgresId gpi = new GenerateProgresId();
    }
}

答案 2 :(得分：1)

试试这个，

class Foo
{
   private static int incr=0;
   public static String getNo()
   {
        incr++;
        if(incr%100==0)
            incr++;
        String no=String.valueOf(incr%100);
        String str= String.valueOf((char)('A'+incr/100)) + new String(new byte[]{'0','0'},0,2-no.length()) + 

String.valueOf(incr%100);
        return str;
   }
}

public class Test
{
  public static void main(String args[]){
      for(int i=1;i<=310;i++){
        System.out.println(Foo.getNo());
      }
  } 
}

答案 3 :(得分：1)

执行此操作的一种方法是分别制作第一个字符和第二个字符。

public SequenceGenerator {
    private int lowerTwoDigits;
    private char thirdDigit;

    public SequenceGenerator () {
        lowerTwoDigits = 0;
        thirdDigit = '0';
    }

    public String nextElement() {
        lowerTwoDigits++;
        if (lowerTwoDigits == 100) {
            lowerTwoDigits = 1;
            thirdDigit++;
            if (thirdDigit == '9' + 1)
                thirdDigit = 'A';
        }

        String result = thirdDigit + 
                        ('0' + lowerTwoDigits / 10 ) + 
                        ('0' + lowerTwoDigits % 10 );

        return result;
    }
}

public class Main {
    public static void main(String[] args) {
        SequenceGenerator s = new SequenceGenerator();

        int MAX = 99 * 36;

        while (MAX >= 0) {
            System.out.println(s.nextElement());
            MAX--;
        }

    }
}

这应该是您要求的，我认为您可以理解nextElement方法中发生了什么。

答案 4 :(得分：1)

这是我的（笨拙但希望是正确的）尝试：

class Program {
    public static void main(String[] args) {
        Incrementer inc = new Incrementer();
        while (inc.hasNext()) {
            System.out.println(inc.getNext());
        }
    }
}

class Incrementer {
    private final static char[] prefixes = { '0', '1', '2', '3', '4', '5', '6',
                                      '7', '8', '9', 'A', 'B', 'C' };
    //all the way to 'Z' if you want, but I'm lazy
    private int currentPrefix = 0;
    private int currentNumber = 0;

    public boolean hasNext() {
        if ((currentPrefix == (prefixes.length - 1)) && currentNumber > 99) {
            return false;
        }
        return true;
    }

    // this may throw ArrayIndexOutOfBoundsException, check hasNext() first
    public String getNext() {
        String result;
        if (currentNumber > 99) {
            currentNumber = 1;
            currentPrefix++;
        }
        result = "" + prefixes[currentPrefix];
        if (currentNumber <= 9) {
            result += "0";
        }
        result += currentNumber;
        currentNumber++;
        return result;
    }
}

答案 5 :(得分：0)

你在找这样的东西..（未经测试）

char ch='a';
int iterations=999;
int count=0;
for(int i=0;i<iterations;i++){
    if(i%100==0){
        ch++;
        count=0;
    }
    System.out.println(ch+""+count);
    count++;
}

答案 6 :(得分：0)

这是一个简单的字母增量器，我相信你可以弄清楚其余的： - ）

public static String incrementAlphabetic(String value, int position) {
    value = value.toUpperCase();

    char c = value.charAt(position);
    c++;

    boolean next = false;
    if (c > 'Z') {
        next = true;
        c = 'A';
    }

    String n = value.substring(0, position)
            + String.valueOf(c)
            + value.substring(position + 1, value.length());

    return (next && position > 0) ? incrementAlphabetic(n, position - 1) : n;
}

public static void main(String[] args) {
    String start = "A";
    for (int i = 0; i < 1000; i++) {
        System.out.println(start = incrementAlphabetic(start, 0));
    }
}
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