Question

是否有一种使用SQL Server 2005插入多行并增加特定字段的简单方法？

注意，我不正在寻找涉及identity列的解决方案 - 请参阅问题的底部以获得解释

（已复制以下架构和数据here in this SQLFiddle。）

例如，请考虑以下表格和数据......

CREATE TABLE #TEMPTABLE (
   [PKID] INT IDENTITY, [FKID] INT, [MYTEXT] VARCHAR(10), [SEQUENCE] INT
)
INSERT INTO #TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE]) VALUES (1, 'one', 1)
INSERT INTO #TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE]) VALUES (1, 'two', 2)

-- Table data
PKID  FKID  MYTEXT  SEQUENCE
1     1     one     1
2     1     two     2

要插入以下数据......

DECLARE @FKID INT
SET @FKID = 1
DECLARE @NEWDATA XML
SET @NEWDATA = '<data><text>three</text><text>four</text></data>'

以下内容是否可以SEQUENCE字段显示为1,2,3,4而不是当前的1,2,3,3？

INSERT INTO #TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE])
SELECT @FKID, 
       X.value('.','VARCHAR(10)'),
       (SELECT ISNULL(MAX([SEQUENCE]),0)+1 FROM #TEMPTABLE WHERE [FKID]=@FKID)
FROM @NEWDATA.nodes('/data/text') AS X(X)

-- Actual result...
PKID  FKID  MYTEXT  SEQUENCE
1     1     one     1
2     1     two     2
3     1     three   3
4     1     four    3  <-- Issue

-- Required result...
PKID  FKID  MYTEXT  SEQUENCE
1     1     one     1
2     1     two     2
3     1     three   3
4     1     four    4

更新

回应@marc_s的评论......

身份将是2005年的最佳解决方案......到目前为止最好的解决方案 - 为什么你明确地排除它并坚持自己滚动？（具有造成重复的所有风险等等......）

相关表格将包含多组SEQUENCE值，每个值都根据FKID值“设置”...因此表格可以保存这些行的数据......

PKID  FKID  MYTEXT  SEQUENCE
1     1     one     1
2     1     two     2
3     1     three   3
4     1     four    4
5     2     ett     1
6     2     tva     2
7     2     tre     3

Answer 1

我无法在2005年进行测试，但您应该可以使用CTE来编号;

DECLARE @FKID INT
SET @FKID = 1
DECLARE @NEWDATA XML
SET @NEWDATA = '<data><text>three</text><text>four</text><text>five</text></data>'

;WITH cte AS (SELECT @FKID FKID, X.value('.','VARCHAR(10)') a, 
                  ROW_NUMBER() OVER (ORDER BY X) r
             FROM @NEWDATA.nodes('/data/text') AS X(X))
INSERT INTO TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE])
SELECT fkid, a,
  (SELECT ISNULL(MAX([SEQUENCE]),0)+r FROM TEMPTABLE WHERE [FKID]=cte.fkid)
FROM cte;

SELECT * FROM TEMPTABLE;

给出了结果：

1    1    one     1
2    1    two     2
3    1    three   3
4    1    four    4
5    1    five    5

<强>更新

如果查询只插入一个FKID，则以下简化版本也会起作用（突出显示当前查询的必要更改）：

INSERT INTO #TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE])
SELECT @FKID, 
       X.value('.','VARCHAR(10)'),
       (SELECT ISNULL(MAX([SEQUENCE]),0)+1 FROM #TEMPTABLE WHERE [FKID]=@FKID)
        + ROW_NUMBER() OVER (ORDER BY (SELECT 1))
FROM @NEWDATA.nodes('/data/text') AS X(X)

(SELECT 1) ROW_NUMBER子句中ORDER BY的目的是避免指定任何特定顺序。如有必要，可将其更改为其他内容（例如X.value('.','VARCHAR(10)'）。

Answer 2

怎么样

    INSERT INTO #TEMPTABLE ([FKID], [MYTEXT], [SEQUENCE])
    SELECT @FKID, 
               X.value('.','VARCHAR(10)'),
              (SELECT ISNULL(Count(*),0)+1 FROM #TEMPTABLE)
    FROM @NEWDATA.nodes('/data/text') AS X(X)

Answer 3

试试这个：

with data as (
  select * from ( values
    (1,1,'one'),
    (2,1,'two'),
    (3,1,'three'),
    (5,1,'five'),
    (6,1,'six')
  ) data(PKID, FKID, MYTEXT)
) 
select lhs.*, sequence = count(*)
from data lhs
left join data rhs on rhs.FKID = lhs.FKID 
  and rhs.PKID <= lhs.PKID
group by 
  lhs.PKID,
  lhs.FKID,
  lhs.MYTEXT

产生这个：

PKID        FKID        MYTEXT sequence
----------- ----------- ------ -----------
1           1           one    1
2           1           two    2
3           1           three  3
5           1           five   4
6           1           six    5

增加SQL插入的序列号

3 个答案: