我有两个列表,我需要比较它们,只返回不在两者中的项目列表。
var listOfIds = new List<int> {1,2,4};
var persons = new ObservableCollection<Person>
{
new Person {Id = 1, Name = "Person 1"},
new Person {Id = 2, Name = "Person 2"},
new Person {Id = 3, Name = "Person 3"},
new Person {Id = 4, Name = "Person 4"}
};
在此示例中,new Person {Id = 3, Name = "Person 3"}
将是结果。
Linq解决方案将是首选。
答案 0 :(得分:38)
不适合你
var listOfIds = new List<int> {1,2,4};
var query = from item in persons
where !listOfIds .Contains( item.id )
select item;
您可以查看更多详情:SQL to LINQ ( Case 7 - Filter data by using IN and NOT IN clause)
答案 1 :(得分:33)
您也可以使用lambda:
var query = persons.Where(item => !listOfIds.Contains(item.Id));
答案 2 :(得分:1)
var list1 = new List<int> {1,2,3,4,5};
var list2 = new List<int> {2,3,4,5,6};
list1.Except(list2); //1 - items removed
list2.Except(list1); //6 - items added
答案 3 :(得分:0)
使用C#中的Linq,您可以执行以下变体,得到相同的结果:
int[] numbers1 = { 1,2,3,4 };
int[] numbers2 = { 3,4,5,6 };
// Ac V Bc, thus complement of A plus the complement of B
IEnumerable<int> differencesVariant1 =
numbers1.Except(numbers2).Union(numbers2.Except(numbers1));
// (A V b)c, thus complement of (set A plus set B)
IEnumerable<int> differencesVariant2 =
numbers1.Union(numbers2).Except(numbers1.Intersect(numbers2));
Console.WriteLine("variant 1:");
foreach (int number in differencesVariant1)
Console.WriteLine(number); // prints: 1,2,5,6
Console.WriteLine("variant 2:");
foreach (int number in differencesVariant2)
Console.WriteLine(number); // prints: 1,2,5,6