我的数据库中有3个表,如下所示: -
(1) users_registration
- username
- email
- acode
(2) vendor_registration
- vid
- vkey
- btype
- email
- pass
- bussname
- regdate
- url
- ownerfname
(3) vorder
- ttime
- vid
- tid
- oid
- uid
- amount
- cardid
users_registration表中的用户名和vorder表中的uid是相同的。
我的代码到目前为止: -
SELECT vo.ttime,vo.vid,vo.tid,vo.oid,vo.uid,vo.amount,vo.cardid, vr.bussname
from vorder vo
INNER JOIN vendor_registration vr ON vo.vid=vr.vid
where uid='".$name_array[$z]."'
order by ttime desc";
应用此代码后,我的页面就像这样 ![在此输入图像说明] [1]
实际上,我想在vid的位置显示我的bussname
e451ffc8-db29-4c08-ac67-0177aec6e2ab as shown in image vendorname,
答案 0 :(得分:1)
SELECT vo.ttime, vr.bussname, vo.tid, vo.oid, vo.uid, vo.amount, vo.cardid
FROM vorder vo
INNER JOIN vendor_registration vr
ON vo.vid = vr.vid
WHERE uid = '".$name_array[$z]."'
ORDER BY ttime DESC