Question

#!/usr/bin/env python
from random import randint
b = randint(0, 100)
print b
a = raw_input("Try your luck, choose number (0-100): ")
if a.isdigit():
    if(a == b):
        print 'great!'
    else:
        print('wrong! that number was %s' % b)
else:
    print "string isn't number"

问题是：
$ python luck.py
62个
试试你的运气，选择号码（0-100）：62
错误！这个数字是62实

Answer 1

您将字符串（raw_input的结果）与数字（randint的结果）进行比较，尝试使用

进行测试

if a.isdigit():
    if(int(a) == b):

Answer 2

b是一个整数。 a是一个字符串。您需要使用int(a)转换它。

此外，ask forgiveness rather than permission可能更加pythonic：

try:
  if (int(a)==b):
     print 'great!'
  else:
     print('wrong! that number was %s' % b)
except ValueError:
  print "string isn't number"

Python迷你游戏无法正常工作

2 个答案: