Question

我的数据库看起来像这样......

id，city，name

1，ajo，肚子亩

2，高山，高山村庄

3，apache交界处，失去了荷兰人

4，apache junction，butterfield

5，apache junction，benson

6，bisbee，Queen mine

......等等

我正在尝试显示列表...

<section>
  <h1>ajo</h1>
  <h2>belly acres</h2>
</section>
<section>
  <h1>alpine</h1>
  <h2>alpine village</h2>
</section>
<section>
  <h1>apache junction</h1>
  <h2>lost dutchman</h2>
  <h2>butterfield</h2>
  <h2>benson</h2>
</section>
<section>
  <h1>bisbee</h1>
  <h2>queen mine</h2>
</section>

我目前使用的代码适用于只有一个名称的城市，但是在Apache Junction的例子中有多个名字，我得到了这个......

<section>
  <h1>apache junction</h1>
</section>
  <h2>lost dutchman</h2>
  <h2>butterfield</h2>
  <h2>benson</h2>
<section>
  <h1>bisbee</h1>
  <h2>queen mine</h2>
</section>

我想在一个部分中显示Apache联结中的所有位置名称。这是我正在使用的代码...

    $previousLevel = "";
    $city_query = $wpdb->get_results( $wpdb->prepare("SELECT name, city FROM locations") );
    foreach ($city_query as $city_list) {
        $city = $city_list->city;
        $name = $city_list->name;
        if ($city != $previousLevel) {
            $dump_list .= '<section><h1>' . $city . '</h1>';
            $dump_list_end = '</section>';
        }
        $dump_list .= '<h2><a href="#">' . $name . '</a></h2>';
        $dump_list .= $dump_list_end;
        $previousLevel = $city; 
    }

任何帮助都将不胜感激。

Answer 1

您可以尝试修改此代码吗？

$previousLevel = "";
$city_query = $wpdb->get_results( $wpdb->prepare("SELECT name, city FROM locations") );
foreach ($city_query as $city_list) {
    $city = $city_list->city;
    $name = $city_list->name;
    if ($city != $previousLevel) {
        if ($previousLevel != "") {
            $dump_list .= '</section>';
        }
        $dump_list .= '<section><h1>' . $city . '</h1>';
        $previousLevel = $city;
    }
    $dump_list .= '<h2><a href="#">' . $name . '</a></h2>';
}

Answer 2

修改后的代码，更长，但更容易理解，并且具有正确的数据转义：

$city_query = $wpdb->get_results( $wpdb->prepare("SELECT name, city FROM locations ORDER BY city, name") );
$cities = array();
foreach ($city_query as $city_list) {
    if (!isset($cities[$city_list->city])) {
        $cities[$city_list->city] = array();
    }
    $cities[$city_list->city][] = $city_list->name;
}
$dump_list = '';
foreach ($cities as $city => $names) {
    $dump_list .= '<section><h1>' . htmlspecialchars($city) . '</h1><h2>';
    $dump_list .= implode('</h2><h2>', array_map('htmlspecialchars', $names));
    $dump_list .= '</section>';
}

显示城市列表以及这些城市中的位置名称

2 个答案: