Question

我写了以下查询

SELECT UNIQUE 
    CITY 
FROM 
    STATION 
WHERE 
    (CITY LIKE '%A' OR 
     CITY LIKE '%E' OR 
     CITY LIKE '%I' OR 
     CITY LIKE '%O' OR 
     CITY LIKE '%U') 
ORDER BY 
    CITY;

这有什么问题？

Answer 1

我认为你可以像这样使用REGEXP_LIKE：

SELECT UNIQUE CITY 
FROM STATION 
WHERE REGEXP_LIKE(CITY, '[AaEeIiOoUu]$') 
ORDER BY CITY;

Answer 2

如果您希望它使用低/高字母，您可以使用UPPER(CITY)，否则一切都很好。

Answer 3

这对我有用（Oracle 11g）：

select distinct
    s.city
from
    station s
where 
    upper(substr(s.city,-1,1)) in ('A','E','I','O','U');

Answer 4

在我看来，这样做会更容易：

import re

a = ['123', '121', '136', '1232', '111', '1a1']
pattern_variable = r'\b([1-9])(?!\1)[1-9]\1\b'

for i in a:
    match = re.match(pattern_variable,i)
    if match != None:
        print(i)

#=> 121

Answer 5

使用上部功能。此功能可以帮助您大写文字。

SELECT DISTINCT CITY 
FROM   STATION 
WHERE  UPPER(CITY) LIKE '%A' 
   OR  UPPER(CITY) LIKE '%E' 
   OR  UPPER(CITY) LIKE '%I' 
   OR  UPPER(CITY) LIKE '%O' 
   OR  UPPER(CITY) LIKE '%U';

Answer 6

以下解决方案适用于Oracle DB：

select distinct(city) 
from station 
where UPPER(substr(city,1,1)) 
in ('A','E','I','O','U');

如果您不使用 UPPER ，那么城市名称以小写字母开头的测试用例将会失败。

Answer 7

我们可以向regexp提供另一个参数来处理区分大小写：

i - 不区分大小写，
c - 区分大小写

例如：

select distinct city 
from station 
where regexp_like(city,'[aeiou]$','i')
order by city

Answer 8

使用正则表达式

SELECT DISTINCT(name) FROM city WHERE LOWER(name) RLIKE '.*[aeiou]$'

Answer 9

最简单的是使用正则表达式：

SELECT 
  CITY 
FROM 
  STATION 
WHERE 
  CITY RLIKE "[aeiouAEIOU]$";

Answer 10

我想这个

document.location.href="/";

Answer 11

您可以将此代码用于您的目的!!

const generateDeviceId = (deviceId)  => (({type: GENERATE_DEVICE_ID, payload: deviceId}));

const resolveLogin = (response) => ({type: RESOLVE_LOGIN, payload: response});

const submitLogin = (email, password) => ({type: SUBMIT_LOGIN, payload: {email, password}});

const requestLogin = (email, password) => ({type: REQUEST_LOGIN, payload: {email, password}});

const loadAbout = () => ({type: LOAD_ABOUT});

const submitLoginEpic = (action$) =>
  action$
    .ofType(SUBMIT_LOGIN)
    .concatMap(({payload}) => [
      generateDeviceId(uuid()),
      requestLogin(payload.email, payload.password)
    ]);

const requestLoginEpic = (action$) =>
  action$
    .ofType(REQUEST_LOGIN)
    .mergeMap(({payload}) => login(payload.email, payload.password)
      .concatMap(({response}) => [resolveLogin(response.content), loadAbout()])

Answer 12

在MySql中

    select distinct city 
    from Station 
    where ( city regexp '.[aeiou]$' );

Answer 13

SELECT UNIQUE CITY FROM STATION 
WHERE 
    (CITY LIKE 'A%' OR 
     CITY LIKE 'E%' OR
     CITY LIKE 'I%' OR 
     CITY LIKE 'O%' OR 
     CITY LIKE 'U%');

％外卡字符应该在字母后面

Answer 14

SELECT
   Distinct(CITY)
FROM
   STATION
WHERE
   UPPER(SUBSTR(CITY,1,1)) IN ('A','E','I','O','U');

它在MySQL中运行。

Answer 15

适用于Oracle

select DISTINCT(CITY) from STATION where upper(SUBSTR(CITY,-1,1)) IN ('A','I','O','E','U');

Answer 16

在SQL Server中，这可能是答案的其他版本

select distinct city 
from station 
where right(city,1) in ('a','e','i','o','u')

Answer 17

如果您使用的是MySQL，请尝试以下解决方案：

SELECT UNIQUE CITY 
FROM STATION 
WHERE (CITY REGEXP '%A$' OR CITY REGEXP '%E$' OR CITY REGEXP '%I$' OR CITY REGEXP '%O$' OR CITY REGEXP '%U$') 
ORDER BY CITY;

在SQL中，我想显示以元音结尾的所有城市的名称

17 个答案: