我认为这更像是一个继承问题,但由于我试图通过实施一个使用它的模式来更好地掌握它,我想我会问我的问题是为了更好地掌握。
如果你使用Specification Pattern,有许多规范都来自规范,你用一个包装器规范类包装它们:
示例:
public class CustomerCreditCheck : Specification<Customer> {
private readonly UnlimitedCreditLimitSpecification unlimitedCreditLimitSpec = new UnlimitedCreditLimitSpecification();
private readonly SufficientCustomerCreditAmountSpec sufficientCustCreditAmtSpec = new SufficientCustomerCreditAmountSpec();
private readonly AcceptableCustomerCreditStatusSpecification acceptCustCreditStatusSpec = new AcceptableCustomerCreditStatusSpecification();
public override bool IsSatisfiedBy(Customer customer) {
return acceptCustCreditStatusSpec
.And(unlimitedCreditLimitSpec.Or(sufficientCustCreditAmtSpec))
.IsSatisfiedBy(customer);
}
}
我的问题是:由于您将客户实体传递给acceptCustCreditStatusSpec的IsSatisfiedBy方法(第一个假设),客户实体如何传递给unlimitedCreditLimitSpec和SufficientCustCreditAmtSpec规范的IsSatisifedBy方法?
谢谢,
答案 0 :(得分:1)
Specification<T>.And
和Specification<T>.Or
方法构建一个Specification<T>
,它接受T
的实例,并根据逻辑定义的规范对其进行测试。
所以Specification<T>.And
看起来像是:
public Specification<T> And(Specification<T> left, Specification<T> right) {
return new SpecificationFromPredicate(
t => left.IsSatisfiedBy(t) && right.IsSatisfiedBy(t)
);
}
public class SpecificationFromPredicate<T> : Specification<T> {
private readonly Func<T, bool> predicate;
public SpecificationFromPredicate(Func<T, bool> predicate) {
this.predicate = predicate;
}
public bool IsSatisfiedBy(T t) { return this.predicate(t); }
}
同样适用于Specification<T>.Or
。
所以重点是
acceptCustCreditStatusSpec
.And(unlimitedCreditLimitSpec.Or(sufficientCustCreditAmtSpec))
是一个规范,给定t
它返回
acceptCustCreditStatusSpec.IsSatisfiedBy(t) &&
(unlimitedCreditLimitSpec.IsSatisfiedBy(t) ||
sufficientCustCreditAmtSpec.IsSatisifedBy(t)
);