如果数字($ nm)下降,下面的代码将回显用户的位置 在这个范围之间让我说我有$ nm =(10,4,3,3,1)的位置将分别是(员工,员工,员工,营销人员,员工)而不是(营销人员,员工,员工,员工,员工) )我如何安排让营销人员先行(营销人员,员工,员工,员工,员工)。
$query = "SELECT DISTINCT username,num FROM user ORDER BY num DESC LIMIT 5";
$result = mysql_query ($query) or die('query error');
while( $line = mysql_fetch_assoc($result)){
$um = $line[username];
$nm = $line[num];
echo "name:$um";
if($nm <= 50){
echo "Position: president";
}else if($nm <= 40){
echo "Position: vice";
}else if($nm <= 30){
echo "Position: manager";
}else if($nm <= 20){
echo "Position: marketer";
}else if($nm <= 10){
echo "Position: staff";
}
答案 0 :(得分:0)
while( $line = mysql_fetch_assoc($result)){
$ums[] = $line[username];
$nms[] = $line[num];
}
usort($nms);
foreach ($nms as $nm){
if($nm <= 50){
echo "Position: president";
}else if($nm <= 40){
echo "Position: vice";
}else if($nm <= 30){
echo "Position: manager";
}else if($nm <= 20){
echo "Position: marketer";
}else if($nm <= 10){
echo "Position: staff";
}
}
答案 1 :(得分:0)
usort可以解决您的问题
但不是你的if / else如果错了吗?
不应该吗?
if($nm <= 10){
echo "Position: staff";
} else if($nm <= 20){
echo "Position: marketer";
} else if($nm <= 30){
echo "Position: manager";
} else if($nm <= 40){
echo "Position: vice";
} else if($nm <= 50){
echo "Position: president";
}