Question

如何显示最高和最低平均成绩？我尝试了其他解决方案，但它无法正常工作

您能帮忙了解如何显示最高平均成绩和最低平均成绩

public static void main(String[] args)
{
    Scanner console = new Scanner (System.in);
    int numStud, numGrade = 0, count = 0, count2 = 0;

    double totalgrades = 0;

    System.out.println("Enter number of students:");
    numStud = console.nextInt();
    System.out.println("Enter number of student grades:");
    numGrade = console.nextInt();
    String[] students = new String [numStud];
    double [][] grades = new double [numStud][numGrade];
    double[] average = new double[numStud];
    String x = console.nextLine();

    System.out.println("");
    while(count<numStud)
    {
        System.out.println("Enter name of student " + (count + 1) + ":");
        students[count] = console.nextLine();
        System.out.println("Enter " + numGrade + " grades:");
        while(count2<numGrade)
        {
            grades[count][count2] = console.nextDouble();
            totalgrades = totalgrades + grades [count][count2];
            count2++;

        }
        average[count] = totalgrades / numGrade;
        totalgrades = 0;
        String y = console.nextLine();
        count2 = 0;
        count++;



}
count = 0;
count2 = 0;
while(count<numStud)
{
    System.out.println("The grades of " + students[count] + " are:");
    while(count2<numGrade)
    {
        System.out.println(grades[count][count2] + " ");
        count2++;
    }
    System.out.println("The average is " + average[count] + ".");
    System.out.println("");
    count2 = 0;
    count++;        
}

Answer 1

假设所有平均成绩保持在average数组中。然后，

Arrays.sort(average);
System.out.print("min = " + average[0] + ", max = " + average[average.length - 1]);

要填写average，您必须：

for(int j = 0; j < grades.length; ++j) {
    int sum = 0;
    for(int i = 0; i < grades[j].length; ++i) sum += grades[j][i];

    average[j] = sum / numGrade;
}

正确填写grades数组。但我建议您将while循环转换为for循环。

Answer 2

要查找最高：

将变量说max设置为第一个元素（或0）
循环整个数组
将每个数组元素的值与max
如果元素值＆gt; max
使用元素值

max

在循环结束时，您将获得数组的最大值。

int max = Integer.MIN_VALUE;
for(int x=0; x<average.length; x++)
    if(average[x] > max)
        max = average[x];

要查找最低：

将变量说min设置为第一个元素（或0）
循环整个数组
将每个数组元素的值与min
如果元素值＆lt; min
使用元素值

min

在循环结束时，您将获得该数组的最小值。

int min = Integer.MAX_VALUE;
for(int x=0; x<average.length; x++)
    if(average[x] < min)
        min = average[x];

显示等级最低和最高

2 个答案: