Question

我正在试图找出如何使用imap和php获取最新的3封电子邮件（SEEN和UNSEEN）。它需要具有资源效率，因为邮箱内部有1000个电子邮件。我认为获取所有标题可能需要太多的资源。

我只需要发件人，主题和日期......

有什么想法吗？感谢任何消化/帮助/解释/提示...

Answer 1

我这样做了：

$mbox = imap_open("{imap.myconnection.com:993/imap/ssl}INBOX", "username", "password");

// get information about the current mailbox (INBOX in this case)
$mboxCheck = imap_check($mbox);

// get the total amount of messages
$totalMessages = $mboxCheck->Nmsgs;

// select how many messages you want to see
$showMessages = 5;

// get those messages    
$result = array_reverse(imap_fetch_overview($mbox,($totalMessages-$showMessages+1).":".$totalMessages));

// iterate trough those messages
foreach ($result as $mail) {

    print_r($mail); 

    // if you want the mail body as well, do it like that. Note: the '1.1' is the section, if a email is a multi-part message in MIME format, you'll get plain text with 1.1
    $mailBody = imap_fetchbody($mbox, $mail->msgno, '1.1');

    // but if the email is not a multi-part message, you get the plain text in '1'
    if(trim($mailBody)=="") {
        $mailBody = imap_fetchbody($mbox, $mail->msgno, '1');
    }

    // just an example output to view it - this fit for me very nice
    echo nl2br(htmlentities(quoted_printable_decode($mailBody)));
}

imap_close($mbox);

PHP-Ref IMAP：http://php.net/manual/en/ref.imap.php

此致星

Answer 2

怎么样？

imap_search($res, 'RECENT');

http://php.net/manual/en/function.imap-search.php

Answer 3

$msgnos = imap_search($mbox, "UNSEEN", SE_UID);
$i=0;
foreach($msgnos as $msgUID) {
    $msgNo = imap_msgno($mbox, $msgUID);
    $head = imap_headerinfo($mbox, $msgNo);
    $mail[$i][] = $msgUID;
    $mail[$i][] = $head->Recent;    
    $mail[$i][] = $head->Unseen;    
    $mail[$i][] = $head->from[0]->mailbox."@".$head->from[0]->host; 
    $mail[$i][] = utf8_decode(imap_utf8($head->subject));   
    $mail[$i][] = $head->udate;
}
return $mail;
imap_close($mbox);

将完成这项工作。

使用imap和php检索最近的3封电子邮件

3 个答案: