Question

我希望使用IMAP从电子邮件帐户收件箱中返回n个（最有可能是10个）最近的电子邮件。

到目前为止，我拼凑了一起：

import imaplib
from email.parser import HeaderParser

M = imaplib.IMAP4_SSL('my.server')
user = 'username'
password = 'password'
M.login(user, password)
M.search(None, 'ALL')
for i in range (1,10):
    data = M.fetch(i, '(BODY[HEADER])')
    header_data = data[1][0][1]
    parser = HeaderParser()
    msg = parser.parsestr(header_data)
    print msg['subject']

这回复电子邮件标题很好，但它似乎是一个半随机的电子邮件集合，而不是最近的10个。

如果有帮助，我将连接到Exchange 2010服务器。其他方法也欢迎，IMAP似乎是最合适的，因为我只想阅读不发送的电子邮件。

Answer 1

sort命令可用，但不保证IMAP服务器支持它。例如，Gmail不支持SORT命令。

要尝试sort命令，您可以替换：
M.search(None, 'ALL')
与
M.sort(search_critera, 'UTF-8', 'ALL')

然后search_criteria将是一个字符串，如：

search_criteria = 'DATE' #Ascending, most recent email last
search_criteria = 'REVERSE DATE' #Descending, most recent email first

search_criteria = '[REVERSE] sort-key' #format for sorting

根据RFC5256，这些是有效的sort-key：
"ARRIVAL" / "CC" / "DATE" / "FROM" / "SIZE" / "SUBJECT" / "TO"

注意：
1.需要charset，尝试US-ASCII或UTF-8所有其他人都不需要IMAP服务器支持 2.还需要搜索critera。 ALL命令是有效的，但有很多。请点击http://www.networksorcery.com/enp/rfc/rfc3501.txt

了解更多信息

IMAP的世界疯狂而疯狂。祝你好运

Answer 2

这是获取emailFrom，emailSubject，emailDate，emailContent等的代码。

import imaplib, email, os
user = "your@email.com"
password = "pass"
imap_url = "imap.gmail.com"
connection = imaplib.IMAP4_SSL(imap_url)
connection.login(user, password)
result, data = connection.uid('search', None, "ALL")
if result == 'OK'
    for num in data[0].split():
    result, data = connection.uid('fetch', num, '(RFC822)')
    if result == 'OK':
         email_message = email.message_from_bytes(data[0][1])
         print('From:' + email_message['From'])
         print('To:' + email_message['To'])
         print('Date:' + email_message['Date'])
         print('Subject:' + str(email_message['Subject']))
         print('Content:' + str(email_message.get_payload()[0]))
connection.close()
connection.logout()

Answer 3

这对我有用〜

import imaplib
from email.parser import HeaderParser
M = imaplib.IMAP4_SSL('my.server')
user = 'username'
password = 'password'
M.login(user, password)
(retcode, messages) =M.search(None, 'ALL')
 news_mail = get_mostnew_email(messages)
for i in news_mail :
    data = M.fetch(i, '(BODY[HEADER])')
    header_data = data[1][0][1]
    parser = HeaderParser()
    msg = parser.parsestr(header_data)
    print msg['subject']

这是获得更新的电子邮件功能：

def get_mostnew_email(messages):
    """
    Getting in most recent emails using IMAP and Python
    :param messages:
    :return:
    """
    ids = messages[0]  # data is a list.
    id_list = ids.split()  # ids is a space separated string
    #latest_ten_email_id = id_list  # get all
    latest_ten_email_id = id_list[-10:]  # get the latest 10
    keys = map(int, latest_ten_email_id)
    news_keys = sorted(keys, reverse=True)
    str_keys = [str(e) for e in news_keys]
    return  str_keys

Answer 4

# get recent one email
from imap_tools import MailBox
with MailBox('imap.mail.com').login('test@mail.com', 'password', 'INBOX') as mailbox:
   for message in mailbox.fetch(limit=1, reverse=True):
       print(msg.date_str, msg.subject)

https://github.com/ikvk/imap_tools

Answer 5

Gmail的解决方法。由于IMAP.sort（'DATE'，'UTF-8'，'ALL'）不适用于gmail，因此我们可以将值和日期插入列表，然后以相反的日期顺序对列表进行排序。可以使用计数器检查前n个邮件。如果有数百封邮件，则此方法将花费几分钟。

    M.login(user,password)
    rv,data= M.search(None,'ALL')
    if rv=='OK':
        msg_list=[]
        for num in date[0].split():
            rv,data=M.fetch(num,'(RFC822)')
            if rv=='OK':
                msg_object={}
                msg_object_copy={}
                msg=email.message_from_bytes(data[0][1])
                msg_date=""
                for val in msg['Date'].split(' '):
                    if(len(val)==1):
                        val="0"+val
                    # to pad the single date with 0
                    msg_date=msg_date+val+" "
                msg_date=msg_date[:-1]
              # to remove the last space
                msg_object['date']= datetime.datetime.strptime(msg_date,"%a, %d %b %Y %H:%M:%S %z")
            # to convert string to date time object for sorting the list
                msg_object['msg']=msg
                msg_object_copy=msg_object.copy()
                msg_list.append(msg_object_copy)
        msg_list.sort(reverse=True,key=lambda r:r['date'])
# sorts by datetime so latest mails are parsed first
        count=0
        for msg_obj in msg_list:
            count=count+1
            if count==n:
                break
            msg=msg_obj['msg']
        # do things with the message

使用IMAP和Python获取最近的电子邮件

5 个答案: