将当前记录与之前的记录进行比较

时间:2011-08-19 06:55:54

标签: php mysql

我是PHP&的新手MySQL的。我通过几个论坛搜索,但不知道如何让这个QUERY工作。希望你们能指导我。

ITEMINFO

--------------------------------------
| ItemNo | Description       | Price |
| AAAAA  | AAAAA description | $1.11 |
| BBBBB  | BBBBB description | $2.22 |
| CCCCC  | CCCCC description | $3.33 |

STOREINFO

-----------------------------------------------------------
| StoreNo | Add1        | Add2 | City     | State | Zip   |
| 11111   | 111 Main St | # 1  | New York | NY    | 10001 |
| 22222   | 222 Main St | # 2  | New York | NY    | 10001 |
| 33333   | 333 Main St | # 3  | New York | NY    | 10001 |
| 44444   | 444 Main St | # 4  | New York | NY    | 10001 |

STOREORDER

-------------------------------
| StoreNo | Quantity | ItemNo |
| 11111   | 10       | AAAAA  |
| 11111   | 5        | BBBBB  |
| 33333   | 50       | BBBBB  |
| 22222   | 20       | AAAAA  |

QUERY:列出已订购的所有商店;以及哪个项目&订购了数量?

$query = "SELECT * FROM STOREINFO ".
    "LEFT JOIN STOREORDER ON STOREINFO.StoreNo = STOREORDER.StoreNo ".
    "LEFT JOIN ITEMINFO ON STOREORDER.ItemNo = ITEMINFO.ItemNo ".
    "ORDER BY STOREINFO.StoreNo ASC";

$result = mysql_query($query) or die(mysql_error());

// Print out the contents of each row into a table 
while($row = mysql_fetch_array($result)){
$CheckStoreNo = trim($row['StoreNo']);
if($CheckStoreNo != "") 
        {
        echo " *print store info* ";
---->>>>    echo " *list ALL item ordered & qty* ";
        }
}
    echo "<hr>";
?>

输出:(已格式化)

Company: Store # 11111
111 Main St, # 1, New York, NY 10001
Tel: 111-111-1111
This store ordered - Item: AAAAA - 10 pc(s)

Company: Store # 11111
111 Main St, # 1, New York, NY 10001
Tel: 111-111-1111
This store ordered - Item: BBBBB - 5 pc(s)

Company: Store # 22222
222 Main St, # 2, New York, NY 10001
Tel:  222-222-2222
This store ordered - Item: AAAAA - 20 pc(s)

Company: Store # 33333
333 Main St, # 3, New York, NY 10001
Tel:  333-333-3333
This store ordered - Item: BBBBB - 50 pc(s)

我设法做到这一点。现在,如果您注意到商店#11111实际上有两(2)个不同商品的订单。而不是ECHO所有重复的公司信息,我只需要一次SAME公司信息ECHO并列出为商店#11111订购的所有商品。

示例:这就是我需要的东西!

Company: Store # 11111
111 Main St, # 1, New York, NY 10001
Tel: 111-111-1111
1) Item: AAAAA - 10 pc(s)
2) Item: BBBBB - 5 pc(s)

Company: Store # 22222
... And so on ...

我根据每家商店的订单列出了所有订单。 (感谢@cularis)。

现在,我如何在每个商店的订单后关闭/结束它?

示例:关闭每个商店的打印目的订单!

Company: Store # 11111
111 Main St, # 1, New York, NY 10001
Tel: 111-111-1111
1) Item: AAAAA - 10 pc(s)
2) Item: BBBBB - 5 pc(s)
------- End of order for Store # 11111 -----

Company: Store # 22222
... List order ...
------- End of order for Store # 22222 -----

2 个答案:

答案 0 :(得分:1)

这不是MySQL,而是PHP问题。

你必须在你的前端这样做:

// Print out the contents of each row into a table 
$OldStoreNo = ""
while($row = mysql_fetch_array($result)){
$CheckStoreNo = trim($row['StoreNo']);
if($CheckStoreNo != "") {
    if($OldStoreNo != $CheckStoreNo) {
        echo " *print store info* ";
        $OldStoreNo = $CheckStoreNo;
    }
    echo " *list item ordered & qty* ";
  }
}

与OldStoreNo一起,您可以跟踪每个商店的当前商品数量,以便在每个商品旁边输出一个数字。

答案 1 :(得分:0)

跟踪while循环中的商店编号 如果它与前一个相同,则打印订单,否则打印storeinfo和订单

//track store_no
$current_store_no = false;

while($row = mysql_fetch_array($result)){
    if (trim($row['StoreNo']) != $current_store_no) {
        //print store info
        $current_store_no = trim($row['StoreNo'])
    }
    //print order info
}