Question

我正在练习我的Scala，即特质，我有点卡住了。我决定在类和特征中绘制X-men物种。

我坚持使用Power属性。我想要一个单一的力量列表

我想要的基本上是：

var Rogue = new HomosapienSuperior()
Rogue.addPower("Super Human Strength")

使用addPower将检查Power的单例列表以查看是否添加了电源，如果未添加电源则抛出异常并告诉用户先将其添加到Power的单例列表中。

object Power {
  val powers = new HashMap[String, String] // power -> description, list of Power!
  val secondaryPowers = new HashMap[String, String]  // "Fly" -> "Can fly"
}

import Power._
import scala.collection.mutable.HashMap

class Power(power: String) {
 //How do I refer to the object/singleton Power list?
}

abstract class Homosapien {
  def name:HashMap[String, String]
  def sex: Sex
}

class HomosapienSuperior(
  val name:HashMap[String, String],
  val sex:Sex,
  val power: Power
) extends Homosapien

所以我正在考虑这样做：

class Power(power: String) {
  var power = List[String]
  def addPower(power: String): List = {
    //check the object Power.powers(power)
    // if not in the object Power throw exception else
    // new list (power) prepend this.power 
  }
 //How do I refer to the object/singleton Power list?
}

但我不知道如何引用对象Power中的变量。

我的代码到目前为止：

object Sex extends Enumeration {
  type Sex = Value
  val male = Value("male")
  val female = Value("female")
  val other = Value("other")
}

object Power {
  val powers = new HashMap[String, String] // power -> description
  val secondaryPowers = new HashMap[String, String] 
}

import Sex._
import Power._
import scala.collection.mutable.HashMap

class Power(power: String) {

}

abstract class Homosapien {
  def name:HashMap[String, String]
  def sex: Sex
}

class HomosapienSuperior(
  val name:HashMap[String, String],
  val sex:Sex
  /*
  val power:HashMap[String, String],
  val secondaryPower:HashMap[String, String] */
) extends Homosapien with power with secondaryPower

class HomosapienSuperiorSuperior(
  val name:HashMap[String, String],
  val sex:Sex
  //val power:HashMap[String, String]
) extends Homosapien with power

trait power {
  val power = List[Power] //power name and description
}

trait secondaryPower {
  val secondaryPower = List[Power] //power name and description
}

注意：我还没有完成关于案例类的章节，阅读Altima的Scala 2ed Book编程。

感谢您的时间。

Answer 1

通过Class访问对象：

Power.powers

agilesteel提供的答案

单例变量和具有该单例变量的mutator的Class

1 个答案: