Question

我一直在尝试编写一个从用户那里获取整数值的程序。整数值将由mutator函数更改，另一个函数将在屏幕上打印。谢谢你的帮助。这是我迄今为止的努力：

#include <vector>
#include <cmath>
#include <boost/tuple/tuple.hpp>

#include "gnuplot-iostream.h"

int main() {
    Gnuplot gp;
    // Create a script which can be manually fed into gnuplot later:
    //    Gnuplot gp(">script.gp");
    // Create script and also feed to gnuplot:
    //    Gnuplot gp("tee plot.gp | gnuplot -persist");
    // Or choose any of those options at runtime by setting the GNUPLOT_IOSTREAM_CMD
    // environment variable.

    // Gnuplot vectors (i.e. arrows) require four columns: (x,y,dx,dy)
    std::vector<boost::tuple<double, double, double, double> > pts_A;

    // You can also use a separate container for each column, like so:
    std::vector<double> pts_B_x;
    std::vector<double> pts_B_y;
    std::vector<double> pts_B_dx;
    std::vector<double> pts_B_dy;

    // You could also use:
    //   std::vector<std::vector<double> >
    //   boost::tuple of four std::vector's
    //   std::vector of std::tuple (if you have C++11)
    //   arma::mat (with the Armadillo library)
    //   blitz::Array<blitz::TinyVector<double, 4>, 1> (with the Blitz++ library)
    // ... or anything of that sort

    for(double alpha=0; alpha<1; alpha+=1.0/24.0) {
        double theta = alpha*2.0*3.14159;
        pts_A.push_back(boost::make_tuple(
             cos(theta),
             sin(theta),
            -cos(theta)*0.1,
            -sin(theta)*0.1
        ));

        pts_B_x .push_back( cos(theta)*0.8);
        pts_B_y .push_back( sin(theta)*0.8);
        pts_B_dx.push_back( sin(theta)*0.1);
        pts_B_dy.push_back(-cos(theta)*0.1);
    }

    // Don't forget to put "\n" at the end of each line!
    gp << "set xrange [-2:2]\nset yrange [-2:2]\n";
    // '-' means read from stdin.  The send1d() function sends data to gnuplot's stdin.
    gp << "plot '-' with vectors title 'pts_A', '-' with vectors title 'pts_B'\n";
    gp.send1d(pts_A);
    gp.send1d(boost::make_tuple(pts_B_x, pts_B_y, pts_B_dx, pts_B_dy));

    return 0;
}

Answer 1

不要传递参数类型的函数：obj.set_account(i)和obj.output(cout)就足够了。请注意，我通过cout而不是out，因为out中未定义main()。请记住，函数定义/声明中的参数名称与您实际传递它的参数的名称无关。

您还缺少函数定义的返回类型。

此外，您应该通过引用传递ostream，而不是按值传递，因为ostream没有定义副本ctor。

c ++中的类访问器和增变器函数

1 个答案: