Question

    create table #Events
(
    EventID int identity primary key,
    StartDate datetime not null,
    EndDate datetime not null
)
go
insert into #Events (StartDate, EndDate)
select '2007-01-01 12:44:12 AM', '2007-01-01 12:45:34 AM' union all
select '2007-01-01 12:45:12 AM', '2007-01-01 12:46:34 AM' union all
select '2007-01-01 12:46:12 AM', '2007-01-01 12:47:34 AM' union all
select '2007-01-02 5:01:08 AM', '2007-01-02 5:05:37 AM' union all
select '2007-01-02 5:50:08 AM', '2007-01-02 5:55:59 AM' union all
select '2007-01-03 4:34:12 AM', '2007-01-03 4:55:18 AM' union all
select '2007-01-07 3:12:23 AM', '2007-01-07 3:52:25 AM'

（向http://www.sqlteam.com/article/working-with-time-spans-and-durations-in-sql-server道歉以收获他们的基础sql）

我正在尝试查找一小时内发生的事件计数，因此结果集看起来像这样：

2007-01-01      12:00     3
2007-01-02       5:00     2
2007-01-03       4:00     1
2007-01-07       3:00     1

我一直在玩dateadd和round并分组，但没有得到它。有人可以帮忙吗？

感谢。

Answer 1

这个怎么样？假设SQL Server 2008：

SELECT CAST(StartDate as date) AS ForDate,
       DATEPART(hour,StartDate) AS OnHour,
       COUNT(*) AS Totals
FROM #Events
GROUP BY CAST(StartDate as date),
       DATEPART(hour,StartDate)

2008年之前：

SELECT DATEADD(day,datediff(day,0,StartDate),0)   AS ForDate,
       DATEPART(hour,StartDate) AS OnHour,
       COUNT(*) AS Totals
FROM #Events
GROUP BY CAST(StartDate as date),
       DATEPART(hour,StartDate)

这导致：

ForDate                 | OnHour | Totals
-----------------------------------------
2011-08-09 00:00:00.000     12       3

Answer 2

或者，只需GROUP BY小时和日期：

SELECT  CAST(Startdate as DATE) as 'StartDate', 
        CAST(DATEPART(Hour, StartDate) as varchar) + ':00' as 'Hour', 
        COUNT(*) as 'Ct'
FROM #Events
GROUP BY CAST(Startdate as DATE), DATEPART(Hour, StartDate)
ORDER BY CAST(Startdate as DATE) ASC

输出：

StartDate   Hour    Ct
2007-01-01  0:00    3
2007-01-02  5:00    2
2007-01-03  4:00    1
2007-01-07  3:00    1

Answer 3

我在其他地方找到了这个。我喜欢这个答案！

SELECT [Hourly], COUNT(*) as [Count]
  FROM 
 (SELECT dateadd(hh, datediff(hh, '20010101', [date_created]), '20010101') as [Hourly]
    FROM table) idat
 GROUP BY [Hourly]

Answer 4

您还可以通过使用以下SQL，在同一列中使用日期和小时以及正确的日期时间格式并按日期时间排序来实现此目的

SELECT  dateadd(hour, datediff(hour, 0, StartDate), 0) as 'ForDate', 
    COUNT(*) as 'Count' 
FROM #Events
GROUP BY dateadd(hour, datediff(hour, 0, LogTime), 0)
ORDER BY ForDate

SQL Server组按每小时的DateTime计数？

4 个答案: