Question

我有会员表

 member_Id
 member_Firstname

另一张表Paymentschedules

  paymentschedule_Id
  member_Id
  paymentschedule_amountdue values(100 rs,200rs)
  paymentschedule_amonutpaid values (30 rs,40 rs)
  paymentschedule_ActualDatetobepaid  values(2011-02-03,2011-02-01,2011-03-01)
  paymentschedule_ datepaid  values like(2011-09-12,2011-08-10,2011-11-12,2010-08-01)

我的问题是，我是否可以将“逾期”的成员名字视为“今天”，并考虑到这些值“ActualDatetobepaid”和“amonutpaid”，“amountdue”和“datepaid”

任何人都可以帮助这个

Answer 1

不确定我理解列的含义，但试试这个：

select distinct member_Firstname 
from member m
join Paymentscedules p on p.member_id = m.member_id
where paymentschedule_ActualDatetobepaid<now() and paymentschedule_amountdue > paymentschedule_amonutpaid

如果您可以为该列和列含义提供数据类型用户，我可以提出更精确的解决方案。

Answer 2

您的上一次请求“添加7天”，通过在J0HN的解决方案中添加7天来解决：

SELECT DISTINCT member_Firstname  
FROM member m 
  JOIN Paymentscedules p ON p.member_id = m.member_id 
WHERE DATE_ADD(paymentschedule_ActualDatetobepaid, INTERVAL 7 DAY)< NOW() 
  AND paymentschedule_amountdue > paymentschedule_amonutpaid

得到非付费会员

2 个答案: