Question

我正在尝试使用以下代码：

args = 'LD_LIBRARY_PATH=/opt/java/jre/lib/i386/:/opt/java/jre/lib/amd64/ exec /opt/java/jre/bin/java -Xincgc -Xmx1G -jar craftbukkit-0.0.1-SNAPSHOT.jar'.split()
p = subprocess.Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

然而，我收到的结果是：

Traceback (most recent call last):
File "launch.py", line 29, in <module>
p = subprocess.Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__ errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1228, in _execute_child raise child_exception
OSError: [Errno 2] No such file or directory

没有LD_LIBRARY_PATH部分，它可以正常工作。但是，我需要它。谢谢你的帮助。

Answer 1

尝试将shell = True添加到Popen来电：

p = subprocess.Popen(args, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

您用于设置LD_LIBRARY_PATH的语法是shell语法，因此必须通过shell执行命令。

Answer 2

这是避免使用shell的方法：

from subprocess import Popen
from os import environ

env = dict(os.environ)
env['LD_LIBRARY_PATH'] = '/opt/java/jre/lib/i386/:/opt/java/jre/lib/amd64/'
args = ['/opt/java/jre/bin/java', '-Xincgc', '-Xmx1G', '-jar', 'craftbukkit-0.0.1-SNAPSHOT.jar']
p = Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, env=env)

子进程和额外的args

2 个答案: