我在具有几个 CTE 的查询中使用 MATCH_RECOGNIZE
函数。当我运行查询时,出现以下错误:
SQL 编译错误:在此上下文中不支持 MATCH_RECOGNIZE。
在我的查询中,在 MATCH_RECOGNIZE 之前和之后有几个 CTE,部分如下。
WITH cte1 AS (
SELECT *
FROM dataset
WHERE ID IS NOT NULL AND STATUS IS NOT NULL ),
cte2 AS (
SELECT *
FROM cte1
QUALIFY FIRST_VALUE(STATUS) OVER (PARTITION BY ID ORDER BY CREATED_AT) = 'created' )
mr as (
SELECT *
FROM cte2
MATCH_RECOGNIZE (
PARTITION BY ID
ORDER BY CREATED_AT
MEASURES MATCH_NUMBER() AS mn,
MATCH_SEQUENCE_NUMBER AS msn
ALL ROWS PER MATCH
PATTERN (c+m+)
DEFINE
c AS status='created'
,m AS status='missing_info'
,p AS status='pending'
) m1
QUALIFY (ROW_NUMBER() OVER(PARTITION BY mn, ID ORDER BY msn) = 1)
OR(ROW_NUMBER() OVER(PARTITION BY mn, ID ORDER BY msn DESC)=1)
ORDER BY ID, CREATED_AT ),
cte3 as (
SELECT *
FROM mr
-- some other operations
)
解决这个问题的理想方法是什么?例如创建常规视图、物化视图或临时表等。我尝试创建视图但出现错误,不确定是否也支持。
如何在其他后续 CTE 中使用 MATCH_RECOGNIZE
的结果?
当我添加以下内容时,会出现此错误:
<块引用>位置 0 处的语法错误行 xx 意外“创建”。
create view filtered_idents AS
SELECT *
FROM cte2
MATCH_RECOGNIZE (
)
答案 0 :(得分:2)
这似乎是一个未记录在案的限制(我要求我们出色的文档团队解决这个问题)。
与此同时,我可以建议将过程分为几个步骤以使用 match_recognize
结果。
重现错误:
with data as (
select $1 company, $2 price_date, $3 price
from values('a',1,10), ('a',2,15)
), cte as (
select *
from data match_recognize(
partition by company
order by price_date
measures match_number() as "MATCH_NUMBER"
all rows per match omit empty matches
pattern(overavg*)
define
overavg as price > avg(price) over (rows between unbounded
preceding and unbounded following)
)
)
select * from cte
-- 002362 (0A000): SQL compilation error: MATCH_RECOGNIZE not supported in this context.
两步解决方案:
with data as (
select $1 company, $2 price_date, $3 price
from values('a',1,10), ('a',2,15)
)
select *
from data match_recognize(
partition by company
order by price_date
measures match_number() as "MATCH_NUMBER"
all rows per match omit empty matches
pattern(overavg*)
define
overavg as price > avg(price) over (rows between unbounded
preceding and unbounded following)
)
;
with previous_results as (
select *
from table(result_scan(last_query_id()))
)
select *
from previous_results
;