我需要替换、格式化字符串以使其与键匹配。
-- 替换符号 ( ) ，不带空格， -- 用下划线替换单个空格， -- 用BD替换BAND
例如x_input = 高等教育工作者 10 级，2 级（受薪） x_output = HEW_HIGHER_EDUCATION_WORKER_LEVEL_10_BD_2_SALARIED
我用嵌套替换编写了代码，它给出了正确的输出模式
select 'Higher Education Worker Level 10, Band 2 (salaried)' as class_0,
replace(replace(replace(upper('Higher Education Worker Level 10, Band 2 (salaried)'), '(', ''), ')', ''), ' ', '_') as class_1,
replace(class_1, ',', '') as class_2,
replace(class_2, 'Band', 'BD') as class_4
有没有更优雅的方法来做到这一点，我正在阅读雪花正则表达式模式匹配帮助，但找不到更干净的方法，而且它嵌套了几次迭代。
任何提示将不胜感激。
谢谢
答案 0 :(得分：1)
对于单个字符的替换和删除，您可以使用 export default function App = () => {
const showOfferDescription = useRef(false);
useEffect(() => {
// Must use a useRef variable here. If I use useState, the values don't update because
// the callback function just keeps a copy to the initial value and not the current value
game.events.on('POINTEROVER', (id) => {
showOfferDescription.current = true;
})
game.events.on('POINTEROUT', (id) => {
showOfferDescription.current = false;
})
}, []);
return (
// Passing a ref to the child doesn't cause re-render on change. I want to trigger
// a re-render in Dashboard everytime I change `showOfferDescription.current`
<Dashboard
showOfferDescription={showOfferDescription}
/>
);
}
，这将大大缩短多个 translate()。
查询结果与问题相同，但代码更少：
replace()一步：
select 'Higher Education Worker Level 10, Band 2 (salaried)' as class_0,
translate(upper(class_0), ' ()', '_') as class_1,
replace(class_1, ',', '') as class_2,
replace(class_2, 'Band', 'BD') as class_4;