Question

我在javascript中有以下函数调用调用php的ajax，我想通过参数传递给javascript函数，我要访问的php页面和所有来自html的div id都遵循我的代码：

/ ------------------------------------------- -------的JavaScript ---------------------------------- /

function getXMLHttp() 
{
var xmlHttp

try
{
//Firefox, Opera 8.0+, Safari
xmlHttp = new XMLHttpRequest();
} 
catch(e)
{
//Internet Explorer
try
{
  xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
}
catch(e)
{
  try
  {
    xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
  }
  catch(e)
  {
    alert("Your browser does not support AJAX!")
    return false;
  }
}
}
return xmlHttp;
}

function MakeRequest() 
{
var xmlHttp = getXMLHttp();

xmlHttp.onreadystatechange = function()
{
if(xmlHttp.readyState == 4)
{
  HandleResponse(xmlHttp.responseText);
}
}

xmlHttp.open("GET", "ajax.php", true);
xmlHttp.send(null);
}

function HandleResponse(response)
{
document.getElementById('ResponseDiv').innerHTML = response;
}

/ ------------------------------------------- ------- PHP ---------------------------------- /

<?php
echo "This is a php response to your request!!!!!!";
?>

/ ------------------------------------------- ------- HTML ---------------------------------- /

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
  <head>
    <script type='text/javascript' src='ajax.js'></script>
    <title>PHP AJAX Example</title>
  </head>
  <body>
    <input type='button' onclick='MakeRequest();' value='Use AJAX!!!!'/>
    <div id='ResponseDiv'>
      This is a div to hold the response.
    </div>
  </body>
</html>

非常感谢你......

Answer 1

别担心，如果你愿意的话，我不会告诉你你不能重新发明轮子。 ^^

function getXMLHttp() 
{
    var xmlHttp

    try
    {
        //Firefox, Opera 8.0+, Safari
        xmlHttp = new XMLHttpRequest();
    } 
    catch(e)
    {
        //Internet Explorer
        try
        {
            xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        }
        catch(e)
        {
            try
            {
                xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
            }
            catch(e)
            {
                alert("Your browser does not support AJAX!")
                return false;
            }
        }
    }
    return xmlHttp;
}

function MakeRequest(page, obj) 
{
    var xmlHttp = getXMLHttp();

    xmlHttp.onreadystatechange = function()
    {
        if(xmlHttp.readyState == 4)
        {
            HandleResponse(xmlHttp.responseText, obj);
        }
    }

    xmlHttp.open("GET", page, true);
    xmlHttp.send(null);
}

function HandleResponse(response, obj)
{
    document.getElementById(obj).innerHTML = response;
}

这是HTML正文组件。注意我使用了“引号”而不是“撇号”。

<input type="button" onclick="MakeRequest('ajax.php', 'ResponseDiv');" value="Use AJAX!!!!"/>
<div id='ResponseDiv'>
  This is a div to hold the response.
</div>

使用ajax和php的javascript函数不能正常工作

1 个答案: