<script type="text/javascript">
function reportPost(args, id) {
var reason = prompt("Reason");
if (reason == null || reason == "") {
return false;
}
$.ajax({
type: "POST",
url: "testajax.php",
data: "reason=" + reason + "&" + args,
success: function(msg) {
var reportSpan = document.getElementById('report' + id);
reportSpan.parentNode.removeChild(reportSpan);
}
});
}
</script>
<span id="report<?php echo $pid ?>"><a href="#" onclick="reportPost('post_id=<?php echo $pid ?>', <?php echo $pid ?>);return false;" rel="nofollow"><img src="exclamation.png" alt="Report" /></a></span>
我在ajax.php中的所有内容是:
mysql_query("INSERT INTO reports (message) VALUES ('test')");
没有任何内容插入到该表中,而且我连接信任我
答案 0 :(得分:0)
首先,您说“ajax.php”中的所有内容都是该命令,但您的脚本是针对testajax.php。