在第4行代码(忽略空白和评论)以及我正在计算2个日期之间的月差异。这有效,但看起来有点hacky。还有更好的方法吗?
int handleAllowance(LocalDate today) {
int allowance = membership.allowance();
if (allowance == 0) return 0;
// if update was last month (or earlier)
int months = today.monthOfYear().getMaximumValue() - today.monthOfYear().getMinimumValue(); // yeah, 12, but just to be 100% correct :-)
int curMonth = (today.getYear() * months) + today. getMonthOfYear();
int updMonth = (lastAllowanceUpdate.getYear() * months) + lastAllowanceUpdate.getMonthOfYear();
if (curMonth > updMonth) {
// ...and if today is on or past update day
int updateDay = Math.min(allowanceDay, today.dayOfMonth().getMaximumValue());
if (today.getDayOfMonth() >= updateDay) {
// number of months to give allowance (in the rare case this process fails to run for 2 months or more)
int allowanceMonths = curMonth - updMonth;
// give credits
final int totalAllowance = allowance * allowanceMonths;
giveCredits(totalAllowance);
// update day
lastAllowanceUpdate = lastAllowanceUpdate.plusMonths(allowanceMonths);
// return the allowance given
return totalAllowance;
}
}
return 0;
}
答案 0 :(得分:27)
Months.monthsBetween(
start.withDayOfMonth(1),
end.withDayOfMonth(1)).getMonths()
答案 1 :(得分:2)
这与Bozho的解决方案非常相似:
public static YearMonth toYearMonth(LocalDate localDate) {
return new YearMonth(localDate.getYear(), localDate.getMonthOfYear());
}
public static int monthSwitches(LocalDate date1,LocalDate date2) {
return Months.monthsBetween(toYearMonth(date1),toYearMonth(date2)).getMonths();
}
答案 2 :(得分:1)
这是我在评论Bozho时提出的解决方案
int handleAllowance(LocalDate today) {
int allowance = membership.allowance();
if (allowance == 0) return 0;
// calculate month difference
int allowanceMonths = Months.monthsBetween(lastAllowanceUpdate.withDayOfMonth(1), today.withDayOfMonth(1)).getMonths();
// if update was last month or earlier
if (allowanceMonths > 0) {
// ...and if today is on or past update day
int updateDay = Math.min(allowanceDay, today.dayOfMonth().getMaximumValue());
if (today.getDayOfMonth() >= updateDay) {
// give credits (multiply with months in the rare case this process consecutively fails to run for 2 months or more)
final int totalAllowance = allowance * allowanceMonths;
giveCredits(totalAllowance);
// update day
lastAllowanceUpdate = lastAllowanceUpdate.plusMonths(allowanceMonths);
// return the allowance given
return totalAllowance;
}
}
return 0;
}