我从http://sourceforge.net/projects/joda-time/files/joda-time/2.2/下载的Joda时间罐有问题。当我使用以下代码段
时,我可以得到结果static void timeDifferencewithJoda() {
String dateStart = "01/14/2012 09:29:58";
String dateStop = "01/15/2012 10:31:48";
SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(dateStart);
d2 = format.parse(dateStop);
DateTime dt1 = new DateTime(d1);
DateTime dt2 = new DateTime(d2);
System.out.print(Days.daysBetween(dt1, dt2).getDays() + " days, ");
System.out.print(Hours.hoursBetween(dt1, dt2).getHours() % 24 + " hours, ");
System.out.print(Minutes.minutesBetween(dt1, dt2).getMinutes() % 60 + " minutes, ");
System.out.print(Seconds.secondsBetween(dt1, dt2).getSeconds() % 60 + " seconds.");
} catch (Exception e) {
e.printStackTrace();
}
}
结果
1 days, 1 hours, 1 minutes, 50 seconds.
但我面对这个时差的冲突。
01/14/2012 09:29:58
01/15/2012 10:31:48
这里宣布了两次,但没有迹象表明像AM或PM这样的时期。即,时间可能是早上或晚上。我如何得到确切的时差?
对此有任何帮助都很有用。
答案 0 :(得分:12)
使用Joda formatter(非AM / PM)
final String dateStart = "01/14/2012 09:29:58";
final String dateStop = "01/15/2012 10:31:48";
final DateTimeFormatter format = DateTimeFormat.forPattern("MM/dd/yyyy HH:mm:ss");
final DateTime dt1 = format.parseDateTime(dateStart);
final DateTime dt2 = format.parseDateTime(dateStop);
System.out.print(Days.daysBetween(dt1, dt2).getDays() + " days, ");
System.out.print(Hours.hoursBetween(dt1, dt2).getHours() % 24 + " hours, ");
System.out.print(Minutes.minutesBetween(dt1, dt2).getMinutes() % 60 + " minutes, ");
System.out.print(Seconds.secondsBetween(dt1, dt2).getSeconds() % 60 + " seconds.");
使用Joda formatter(使用AM / PM)
final String dateStart = "01/14/2012 09:29:58 AM";
final String dateStop = "01/15/2012 10:31:48 PM";
final DateTimeFormatter format = DateTimeFormat.forPattern("MM/dd/yyyy hh:mm:ss a");
final DateTime dt1 = format.parseDateTime(dateStart);
final DateTime dt2 = format.parseDateTime(dateStop);
System.out.print(Days.daysBetween(dt1, dt2).getDays() + " days, ");
System.out.print(Hours.hoursBetween(dt1, dt2).getHours() % 24 + " hours, ");
System.out.print(Minutes.minutesBetween(dt1, dt2).getMinutes() % 60 + " minutes, ");
System.out.print(Seconds.secondsBetween(dt1, dt2).getSeconds() % 60 + " seconds.");
使用Period
计算单位 final Period period = new Period(dt1, dt2);
System.out.print(period.getDays() + " days, ");
System.out.print(period.getHours() + " hours, ");
System.out.print(period.getMinutes() + " minutes, ");
System.out.print(period.getSeconds() + " seconds.");
答案 1 :(得分:0)
在您的SimpleDateFormat中,您有HH指定小时数,并且如文档中所述,HH代表 - 白天小时(0-23)。因此AM / PM不适用于此处。如果您想要AM / PM小时,则应使用KK或hh代替。您可以查看文档here。