junit和easymock，保存时例外

Question

我正在使用EasyMock和JUnit。我在保存时遇到异常。请在下面找到代码。

EasyMock.expect（someDao.save（pojo））。andReturn（pojo）; // pojo我用值创建 EasyMock.replay（someDao）;

Pojo savedObject = someService.save（pojo）;

但 someService.save（pojo）在保存之前再调用一个服务。那怎么可以嘲笑那个服务？

谢谢， 大卫

Answer 1

以同样的方式：

SomeDao someDao = createMock(SomeDao.class);
SomeOtherDao someOtherDao = createMock(SomeOtherDao.class);
someService.setSomeDao(someDao);
someService.setSomeOtherDao(someOtherDao);
EasyMock.expect(someOtherDao.save(pojo)).andReturn(pojo);
EasyMock.expect(someDao.save(pojo)).andReturn(pojo);
EasyMock.replay(someOtherDao, someDao);

Pojo savedObject = someService.save(pojo);