SendInput和64位

时间:2011-07-26 13:22:57

标签: .net pinvoke 64-bit sendinput

以下是我用于通过SendInput API模拟按键的一些代码的摘录。如果我将我的应用程序设置为为x86 CPU编译,但这对x64 CPU编译不起作用,则此方法可以正常工作。

我猜它有一些东西,因为x64使用双倍大小的指针,但我试图将此[FieldOffset(4)]更改为此[FieldOffset(8)],但它不起作用。

它是否与导入32位版本的user32.dll的事实有关?

    #region SendInput API

    [DllImport("user32.dll", EntryPoint = "SendInput", SetLastError = true)]
    static extern uint SendInput(uint nInputs, INPUT[] pInputs, int cbSize);

    [DllImport("user32.dll", EntryPoint = "GetMessageExtraInfo", SetLastError = true)]
    static extern IntPtr GetMessageExtraInfo();

    private enum KeyEvent
    {
        KeyUp = 0x0002,
        KeyDown = 0x0000,
        ExtendedKey = 0x0001
    }

    private struct KEYBDINPUT
    {
        public ushort wVk;
        public ushort wScan;
        public uint dwFlags;
        public long time;
        public uint dwExtraInfo;
    };

    [StructLayout(LayoutKind.Explicit, Size = 28)]
    private struct INPUT
    {
        [FieldOffset(0)]
        public uint type;
        [FieldOffset(4)]
        public KEYBDINPUT ki;
    };

    #endregion

    public void sendKey(KeyCode Key)
    {
        INPUT[] InputList = new INPUT[2];

        INPUT keyInput = new INPUT();
        keyInput.type = 1;

        keyInput.ki.wScan = 0;
        keyInput.ki.time = 0;
        keyInput.ki.dwFlags = (int)KeyEvent.KeyDown;
        keyInput.ki.dwExtraInfo = (uint)GetMessageExtraInfo();
        keyInput.ki.wVk = (ushort)Key;

        InputList[0] = keyInput;

        keyInput.ki.dwFlags = (int)KeyEvent.KeyUp;

        InputList[1] = keyInput;

        SendInput((uint)2, InputList, Marshal.SizeOf(InputList[0]));
    }

2 个答案:

答案 0 :(得分:12)

除了SLaks发现的错误之外,您剩下的问题是INPUT的大小不正确。这意味着SendInput失败,因为它收到INPUT[]类型的参数。您无法使用StructLayout(LayoutKind.Explicit, Size = 28)指定大小,因为您需要同时处理x86和x64的代码。

这一切都源于您只在KEYBRDINPUT中包含INPUT结构的事实。 MOUSEINPUT结构大于KEYBRDINPUT,这是导致问题的原因。

最佳解决方案是正确定义INPUT结构,包括联合部分。这样做(从pinvoke.net获取声明)。

[StructLayout(LayoutKind.Sequential)]
struct MOUSEINPUT
{
    public int dx;
    public int dy;
    public uint mouseData;
    public uint dwFlags;
    public uint time;
    public IntPtr dwExtraInfo;
}

[StructLayout(LayoutKind.Sequential)]
struct KEYBDINPUT 
{
     public ushort wVk;
     public ushort wScan;
     public uint dwFlags;
     public uint time;
     public IntPtr dwExtraInfo;
}

[StructLayout(LayoutKind.Sequential)]
struct HARDWAREINPUT
{
     public int uMsg;
     public short wParamL;
     public short wParamH;
}

[StructLayout(LayoutKind.Explicit)]
struct MouseKeybdHardwareInputUnion
{
    [FieldOffset(0)]
    public MOUSEINPUT mi;

    [FieldOffset(0)]
    public KEYBDINPUT ki;

    [FieldOffset(0)]
    public HARDWAREINPUT hi;
}

[StructLayout(LayoutKind.Sequential)]
struct INPUT
{
    public uint type;
    public MouseKeybdHardwareInputUnion mkhi;
}

答案 1 :(得分:5)

dwExtraInfo是一个指针 因此,它需要在32位代码中为4字节宽,在64位代码中为8字节。

要在C#中执行此操作,请使用IntPtr(不是uint,总是4个字节)