Question

假设我有一个 url，我尝试获取重定向的 url。我使用了以下代码：

useEffect(() => {
    const getAlbumCollection = async () => {
      try {
        const response = await axios({
          url: "http://localhost:5000/api/albums",
          method: "get",
          data: {
            userId: isAuth.id,
          },
        });
        console.log(response);
      } catch (error) {
        console.log(error.message);
      }
    };

    getAlbumCollection();
  }, []);

即使在 java 编译器中似乎可以工作，我在 android 中也会出现以下错误（从 logcat 复制粘贴）。

fun getRedirectUrl(url: String?): String? {
        var urlTmp: URL? = null
        var redUrl: String? = null
        var connection: HttpURLConnection? = null
        try {
            urlTmp = URL(url)
        } catch (e1: MalformedURLException) {
            e1.printStackTrace()
        }
        try {
            connection = urlTmp!!.openConnection() as HttpURLConnection
        } catch (e: IOException) {
            e.printStackTrace()
        }
        try {
            connection!!.responseCode
        } catch (e: IOException) {
            e.printStackTrace()
        }
        redUrl = connection!!.url.toString()
        connection.disconnect()
        return redUrl
    }

我也知道这个 post。为什么会发生这种情况？有什么想法吗？

Answer 1

问题是我不应该在主线程上运行这样的代码。使用 AsyncTask 解决了这个问题。示例

private class getRedirectUrl(url:String) : AsyncTask<String?, Int?, String>() {
        val url = url
        override fun doInBackground(vararg p0: String?): String {
            var urlTmp: URL? = null
            var redUrl: String? = null
            var connection: HttpURLConnection? = null
            try {
                urlTmp = URL(url)
            } catch (e1: MalformedURLException) {
                e1.printStackTrace()
            }
            try {
                connection = urlTmp!!.openConnection() as HttpURLConnection
            } catch (e: IOException) {
                e.printStackTrace()
            }
            try {
                connection!!.responseCode
            } catch (e: IOException) {
                e.printStackTrace()
            }
            redUrl = connection!!.url.toString()
            connection.disconnect()
            return redUrl
        }

        override fun onPostExecute(result: String?) {
            super.onPostExecute(result)
            Log.d("Redirected URL",""+result)
        }
    }

现在您可以使用

获取重定向的网址

  getRedirectUrl("the url you want to get redirect").execute()

从 url android 获取最终重定向的 url

1 个答案: