我有一个重定向到另一个网址的网址。我希望能够获得最终重定向的网址。我的代码:
public class testURLConnection
{
public static void main(String[] args) throws MalformedURLException, IOException {
HttpURLConnection con =(HttpURLConnection) new URL( "http://tinyurl.com/KindleWireless" ).openConnection();
System.out.println( "orignal url: " + con.getURL() );
con.connect();
System.out.println( "connected url: " + con.getURL() );
InputStream is = con.getInputStream();
System.out.println( "redirected url: " + con.getURL() );
is.close();
} }
它总是提供原始网址,而redirectURL是:http://www.amazon.com/Kindle-Wireless-Reading-Display-Globally/dp/B003FSUDM4/ref=amb_link_353259562_2?pf_rd_m=ATVPDKIKX0DER&pf_rd_s=center-10&pf_rd_r=11EYKTN682A79T370AM3&pf_rd_t=201&pf_rd_p=1270985982&pf_rd_i=B002Y27P3M。
如何获得此最终重定向网址。
这是我尝试使用循环直到我们获得重定向的内容。仍然可以获取所需的网址:
public static String fetchRedirectURL(String url) throws IOException
{
HttpURLConnection con =(HttpURLConnection) new URL( url ).openConnection();
//System.out.println( "orignal url: " + con.getURL() );
con.setInstanceFollowRedirects(false);
con.connect();
InputStream is = con.getInputStream();
if(con.getResponseCode()==301)
return con.getHeaderField("Location");
else return null;
}
public static void main(String[] args) throws MalformedURLException, IOException {
String url="http://tinyurl.com/KindleWireless";
String fetchedUrl=fetchRedirectURL(url);
System.out.println("FetchedURL is:"+fetchedUrl);
while(fetchedUrl!=null)
{ url=fetchedUrl;
System.out.println("The url is:"+url);
fetchedUrl=fetchRedirectURL(url);
}
System.out.println(url);
}
答案 0 :(得分:14)
试试这个,我递归使用许多重定向网址。
public static String getFinalURL(String url) throws IOException {
HttpURLConnection con = (HttpURLConnection) new URL(url).openConnection();
con.setInstanceFollowRedirects(false);
con.connect();
con.getInputStream();
if (con.getResponseCode() == HttpURLConnection.HTTP_MOVED_PERM || con.getResponseCode() == HttpURLConnection.HTTP_MOVED_TEMP) {
String redirectUrl = con.getHeaderField("Location");
return getFinalURL(redirectUrl);
}
return url;
}
并使用:
public static void main(String[] args) throws MalformedURLException, IOException {
String fetchedUrl = getFinalURL("<your_url_here>");
System.out.println("FetchedURL is:" + fetchedUrl);
}
答案 1 :(得分:4)
public static String getFinalRedirectedUrl(String url) {
HttpURLConnection connection;
String finalUrl = url;
try {
do {
connection = (HttpURLConnection) new URL(finalUrl)
.openConnection();
connection.setInstanceFollowRedirects(false);
connection.setUseCaches(false);
connection.setRequestMethod("GET");
connection.connect();
int responseCode = connection.getResponseCode();
if (responseCode >= 300 && responseCode < 400) {
String redirectedUrl = connection.getHeaderField("Location");
if (null == redirectedUrl)
break;
finalUrl = redirectedUrl;
System.out.println("redirected url: " + finalUrl);
} else
break;
} while (connection.getResponseCode() != HttpURLConnection.HTTP_OK);
connection.disconnect();
} catch (Exception e) {
e.printStackTrace();
}
return finalUrl;
}
答案 2 :(得分:2)
我的第一个想法是将instanceFollowRedirects
设置为false,或者使用URLConnection
代替。
在这两种情况下,重定向都不会被执行,因此您将收到对原始请求的回复。获取HTTP状态值,如果是3xx,则获取新的重定向值。
当然可能存在一系列重定向,因此您可能需要进行迭代,直至到达真实(状态2xx)页面。
答案 3 :(得分:1)
@ user719950在我的MAC-OSX上 - 这解决了截断的HTTP URL问题:
在原始代码中,只需将以下内容添加到以下行://您必须通过浏览器找到IE / Chrome正在发送的请求标头。我仍然没有解释为什么这个简单的设置导致正确的URL:)
HttpURLConnection con =(HttpURLConnection) new URL
( "http://tinyurl.com/KindleWireless" ).openConnection();
con.setInstanceFollowRedirects(true);
con.setDoOutput(true);
System.out.println( "orignal url: " + con.getURL() );
**con.setRequestProperty("User-Agent",
"Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_2)
AppleWebKit/536.26.17 (KHTML, like Gecko) Version/6.0.2
Safari/536.26.17");**
con.connect();
System.out.println( "connected url: " + con.getURL() );
Thread.currentThread().sleep(2000l);
InputStream is = con.getInputStream();
System.out.println( "redirected url: " + con.getURL() );
is.close();
答案 4 :(得分:1)
这可能会有所帮助
public static void main(String[] args) throws MalformedURLException,
IOException {
HttpURLConnection con = (HttpURLConnection) new URL(
"http://tinyurl.com/KindleWireless").openConnection(proxy);
System.out.println("orignal url: " + con.getURL());
con.connect();
con.setInstanceFollowRedirects(false);
int responseCode = con.getResponseCode();
if ((responseCode / 100) == 3) {
String newLocationHeader = con.getHeaderField("Location");
responseCode = con.getResponseCode();
System.out.println("Redirected Location " + newLocationHeader);
System.out.println(responseCode);
}
}
答案 5 :(得分:0)
@JEETS 您的fetchRedirectURL函数可能无法正常工作,因为重定向有多种HTTP代码。将其更改为范围检查,它将起作用。
public static String fetchRedirectURL(String url) throws IOException
{
HttpURLConnection con =(HttpURLConnection) new URL( url ).openConnection();
//System.out.println( "orignal url: " + con.getURL() );
con.setInstanceFollowRedirects(false);
con.connect();
InputStream is = con.getInputStream();
if(con.getResponseCode()>=300 && con.getResponseCode() <400)
return con.getHeaderField("Location");
else return null;
}
答案 6 :(得分:0)
如果存在多个重定向,则会递归递送:
protected String getDirectUrl(String link) {
String resultUrl = link;
HttpURLConnection connection = null;
try {
connection = (HttpURLConnection) new URL(link).openConnection();
connection.setInstanceFollowRedirects(false);
connection.connect();
int responseCode = connection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_MOVED_PERM || responseCode == HttpURLConnection.HTTP_MOVED_TEMP) {
String locationUrl = connection.getHeaderField("Location");
if (locationUrl != null && locationUrl.trim().length() > 0) {
IOUtils.close(connection);
resultUrl = getDirectUrl(locationUrl);
}
}
} catch (Exception e) {
log("error getDirectUrl", e);
} finally {
IOUtils.close(connection);
}
return resultUrl;
}