Question

我正在尝试运行以下代码，希望它异步运行。

import threading
import time


def mock_app(widgets=None, filters=None):
    print('Mock app called')
    task = threading.Thread(target=mock_app_handler(), args=())
    task.start()
    print('Thread spawned')
    return "success"


def mock_app_handler():
    # do something
    print('doing something')
    time.sleep(2)
    print('done something')


print(mock_app())

但是，代码是同步执行的。我得到以下结果。

Mock app called
doing something
done something
Thread spawned
success

为什么会这样？我错过了什么吗？

更新：我尝试设置 task.daemon = True。那也没有用。

Answer 1

问题是，您调用的是函数 <div class="row"> <div class="col-md-4 "> <div class="box "> <div class="img-box"> <img src="images/solar.png" alt="solar"> </div> <div class="detail-box"> <h5> Solar Panel Systems </h5> <p> Do you need something that isn't on the website? Do you need to to consult someone on<span id="dots5">...</span><span id="more5" style="display: none;"> something that has been bothering you with your devices, cameras, phones, alarms, solar panels? Do you need advice? Contact Us! IT'S FREE!!!</span> </p> <button type="button" id="solar" onclick="solar()">Read More</button> </div> </div> </div> </div> 而不是传递函数对象。 threading.Thread 中的 mock_app_handler 需要一个可调用对象。所以

代替

target

使用

task = threading.Thread(target=mock_app_handler(), args=())

此外，您不需要传递空的 task = threading.Thread(target=mock_app_handler)，因为函数 args 不需要任何 mock_app_handler。

Python线程异步运行

1 个答案: