假设我的屏幕大小为 10, 10
和 2, 2 的 pos
如果屏幕大小更改为 5, 5
pos 将是 1, 1
或者有没有办法改变屏幕分辨率?
答案 0 :(得分:0)
turtle 会自动设置一个 ScrolledCanvas
,因此,调整窗口大小会尝试将事物保持在大致相同的位置,但存在限制。
您可以先将海龟放在成比例的位置,然后从该比例开始绘制。
只需将您的大小和移动视为窗口的分区。使用对角线作为主要维度,然后从那里开始。
这就是可缩放矢量图形的本质 -- https://en.wikipedia.org/wiki/Vector_graphics
#! /usr/bin/python3
from math import sqrt
from random import uniform
from turtle import Turtle, Screen
turtle, screen = Turtle(), Screen()
turtle.penup()
turtle.speed( 0 )
red, green, blue = 0.95, 0.95, 0.95
screen.bgcolor( red, green, blue )
##Width, Height = 300, 300
Width, Height = 600, 600
## Pythag. A squared +B squared = C squared
Diag = sqrt( (Width *Width) +(Height *Height) )
stepsize = Diag /100
screen.screensize( Width, Height ) ## canvas size to begin with
## window frame. by adding a few pixels, you avoid scrollbars
screen.setup( width = Width *1.03, height = Height *1.03 )
for i in range( 50 ): ## clouds
light = uniform( 0.8, 1 )
turtle.pencolor( light, light, light )
turtle.pensize( stepsize *uniform( 0.5, 5 ) )
turtle.setheading( uniform( 0.0, 360 ) )
turtle.goto( Width *uniform( -0.5, 0.5 ), Height *uniform( 0.0, 0.5 ) )
turtle.pendown()
turtle.forward( stepsize *uniform( 0.1, 1 ) )
turtle.penup()
red, green, blue = 0.0, 0.25, 0.5
for i in range( 25 ): ## scribble water
green += 0.01
blue += 0.02
water_level = Height *0.15 +(i *stepsize)
turtle.goto( -Width *0.55, -water_level )
turtle.pencolor( red, green, blue )
turtle.pensize( stepsize +i )
turtle.pendown()
turtle.goto( Width *0.55, -water_level )
turtle.penup()
red, green, blue = 0.95, 0.95, 0.95
turtle.goto( Width *0.25, Height *0.333 )
turtle.setheading( 45 )
turtle.pendown()
for i in range( 20 ): ## draw sun
red -= 0.0111
green -= 0.02
blue -= 0.0225
turtle.pencolor( red, green, blue )
turtle.pensize( stepsize *(30 -i) )
turtle.forward( stepsize /5 )
turtle.hideturtle()
screen.exitonclick()
## eof ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~