Question

我正在做一个机器学习作业，在那里我查看错误数据库，进行多类分类，然后插入一个包含分类文本的新列。作为调试的一部分，当我再次运行该特定单元格时，它说列已经存在。我只是想知道是否有办法克服它（除了通常的异常处理）。

我写的那段代码如下：

trigger_dict = {
    'Config-Change':['change','changing','changed'], \
    'Upgrade-Downgrade':['Upgrade','Downgrade','ISSU'], \
    'VPC-Related':['MCT','MCEC','VPC'], \
    'CLI-Related':['CC','Consistency','Checker','Show','Debug','Clear'], \
    'Interface-Flap': ['Flap','Shut'] ,\
    'Reload-Related': ['reload','reboot','ASCII','Replay'],\
    'Process-Related': ['Restart','Kill','Process'],\
    'ACL-Related': ['RACL','PACL','IFACL'],\
    'Config-Unconfig': ['config','remove','removal','Unconfig','reconfig'],\
    'HA-Related': ['SSO','LC','Switchover'],\
}


cat_1 = pd.Series([])
flag = 0

for index in range(df['Headline'].shape[0]):
    text = df['Headline'][index]
    for key, value in trigger_dict.items():
        for val in value:
            if re.search(val, text, re.I):
                if not flag:
                    cat_1[index] = key
                    flag = 1
    flag = 0
        
df.insert(len(df.columns),"Trigger_Type", cat_1)


---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-45-d23348f7bbac> in <module>
     12     flag = 0
     13 
---> 14 df.insert(len(df.columns),"Trigger_Type", cat_1)

~/Desktop/Anaconda/anaconda3/envs/nlp_course/lib/python3.7/site-packages/pandas/core/frame.py in insert(self, loc, column, value, allow_duplicates)
   3220         value = self._sanitize_column(column, value, broadcast=False)
   3221         self._data.insert(loc, column, value,
-> 3222                           allow_duplicates=allow_duplicates)
   3223 
   3224     def assign(self, **kwargs):

~/Desktop/Anaconda/anaconda3/envs/nlp_course/lib/python3.7/site-packages/pandas/core/internals.py in insert(self, loc, item, value, allow_duplicates)
   4336         if not allow_duplicates and item in self.items:
   4337             # Should this be a different kind of error??
-> 4338             raise ValueError('cannot insert {}, already exists'.format(item))
   4339 
   4340         if not isinstance(loc, int):

ValueError: cannot insert Trigger_Type, already exists

Answer 1

它不起作用，因为您已经有一个具有该名称的列。如果您可以接受重复的列，则可以传递 allow_duplicates=True。

df.insert(len(df.columns),"Trigger_Type", cat_1, allow_duplicates=True)

否则，您必须将该列重命名为其他名称。

如果要完全替换列，也可以使用：

df['Trigger_Type'] = cat1

在现有的熊猫数据框中插入一个新列

1 个答案: