Question

给定两个数据框如下：

df1：

   id                                      address  price
0   1         8563 Parker Ave. Lexington, NC 27292      3
1   2         242 Bellevue Lane Appleton, WI 54911      3
2   3       771 Greenview Rd. Greenfield, IN 46140      5
3   4       93 Hawthorne Street Lakeland, FL 33801      6
4   5  8952 Green Hill Street Gettysburg, PA 17325      3
5   6    7331 S. Sherwood Dr. New Castle, PA 16101      4

df2：

  state            street  quantity
0    PA       S. Sherwood        12
1    IN  Hawthorne Street         3
2    NC       Parker Ave.         7

假设 state 的 street 和 df2 都包含在 address 的 df2 中，然后将 df2 合并到 {{1 }}。

我怎么能在 Pandas 中做到这一点？谢谢。

预期结果df1：

df

我的测试代码：

   id                                      address  ...       street quantity
0   1         8563 Parker Ave. Lexington, NC 27292  ...  Parker Ave.     7.00
1   2         242 Bellevue Lane Appleton, WI 54911  ...          NaN      NaN
2   3       771 Greenview Rd. Greenfield, IN 46140  ...          NaN      NaN
3   4       93 Hawthorne Street Lakeland, FL 33801  ...          NaN      NaN
4   5  8952 Green Hill Street Gettysburg, PA 17325  ...          NaN      NaN
5   6    7331 S. Sherwood Dr. New Castle, PA 16101  ...  S. Sherwood    12.00

[6 rows x 6 columns]

输出：

df2['addr'] = df2['state'].astype(str) + df2['street'].astype(str)

pat = '|'.join(r'\b{}\b'.format(x) for x in df2['addr'])
df1['addr']= df1['address'].str.extract('\('+ pat + ')', expand=False)

df = df1.merge(df2, on='addr', how='left')

Answer 1

k="|".join(df2['street'].to_list())
df1=df1.assign(temp=df1['address'].str.findall(k).str.join(', '), temp1=df1['address'].str.split(",").str[-1])
dfnew=pd.merge(df1,df2, how='left', left_on=['temp','temp1'], right_on=['street',"state"])

Answer 2

尝试：

pat_state = f"({'|'.join(df2['state'])})"
pat_street = f"({'|'.join(df2['street'])})"
df1['street'] = df1['address'].str.extract(pat=pat_street) 
df1['state'] = df1['address'].str.extract(pat=pat_state) 
df1.loc[df1['state'].isna(),'street'] = np.NAN
df1.loc[df1['street'].isna(),'state'] = np.NAN
df1 = df1.merge(df2, left_on=['state','street'], right_on=['state','street'], how ='left')

如果两个字符串列是 Python 中另一个数据帧中一列的子字符串，则合并

2 个答案: