Question

我正在使用MySQL，我有两个表：

master_table

ORDERNO
ITEM
QTY

stock_bal

ITEM
BAL_QTY

主表格具有重复的ORDERNO和ITEM值。我使用SQL'GROUP BY'子句得到总QTY。

我需要从BAL_QTY（master_table）的SUM中扣除/减去ITEM。我使用查询获得了SUM QTY值（实际上有很多行）。

Answer 1

我认为这就是你要找的东西。 NEW_BAL是从余额中减去QTY的总和：

SELECT   master_table.ORDERNO,
         master_table.ITEM,
         SUM(master_table.QTY),
         stock_bal.BAL_QTY,
         (stock_bal.BAL_QTY - SUM(master_table.QTY)) AS NEW_BAL
FROM     master_table INNER JOIN
         stock_bal ON master_bal.ITEM = stock_bal.ITEM
GROUP BY master_table.ORDERNO,
         master_table.ITEM

如果要使用新余额更新项目余额，请使用以下命令：

UPDATE stock_bal
SET    BAL_QTY = BAL_QTY - (SELECT   SUM(QTY)
                            FROM     master_table
                            GROUP BY master_table.ORDERNO,
                                     master_table.ITEM)

这假设您向后发布了减法;它从天平中减去订单中的数量，这在不了解您的表格的情况下最有意义。如果我错了，只需交换这两个就改变它：

(SUM(master_table.QTY) - stock_bal.BAL_QTY) AS NEW_BAL

Answer 2

我不确定你想要什么，但我认为这与以下几行有关：

SELECT `Item`, `qty`-`BAL_QTY` as `qty` FROM ((SELECT Item, SUM(`QTY`) as qty FROM `master_table` GROUP BY `ITEM`) as A NATURAL JOIN `stock_table`) as B

Answer 3

啊做作业......

等等，您需要从已订购商品的总数中扣除库存商品的余额吗？我必须告诉你，听起来有些倒退。一般来说，我认为人们会这样做。扣除从余额中订购的物品总数。

如果你确实需要那样做...... 假设ITEM在stock_bal中是独一无二的......

SELECT s.ITEM, SUM(m.QTY) - s.QTY AS result
FROM stock_bal s
INNER JOIN master_table m ON m.ITEM = s.ITEM
GROUP BY s.ITEM, s.QTY

Answer 4

我尝试过这种技术。将数据的减法乘以（-1）然后求和（）两者的数量，然后你将得到减去的金额。

-- Loan Outstanding
    select  'Loan Outstanding' as Particular, sum(Unit), sum(UptoLastYear), sum(ThisYear), sum(UptoThisYear)
    from
    (
        select 
            sum(laod.dr) as Unit,
            sum(if(lao.created_at <= '2014-01-01',laod.dr,0)) as UptoLastYear,
            sum(if(lao.created_at between '2014-01-01' and '2015-07-14',laod.dr,0)) as ThisYear,
            sum(if(lao.created_at <= '2015-07-14',laod.dr,0)) as UptoThisYear
        from loan_account_opening as lao
        inner join loan_account_opening_detail as laod on lao.id=laod.loan_account_opening_id
        where lao.organization = 3
        union
        select
            sum(lr.installment)*-1 as Unit,
            sum(if(lr.created_at <= '2014-01-01',lr.installment,0))*-1 as UptoLastYear,
            sum(if(lr.created_at between '2014-01-01' and '2015-07-14',lr.installment,0))*-1 as ThisYear,
            sum(if(lr.created_at <= '2015-07-14',lr.installment,0))*-1 as UptoThisYear
        from loan_recovery as lr
        inner join loan_account_opening as lo on lr.loan_account_opening_id=lo.id
        where lo.organization = 3
    ) as t3

Answer 5

下面给出了一个减法示例：

Select value1 - (select value2 from AnyTable1) from AnyTable2

value1和value2可以是计数，求和，平均输出等。但是这些值应该兼容

Answer 6

带有子查询的简单复制和粘贴示例，请注意，两个查询都应返回1行：

select
(select sum(items_1) from items_table_1 where ...)
-
(select count(items_2) from items_table_1 where ...) 

as difference

如何使用SQL进行SUM和SUBTRACT？

6 个答案: